<span>assume z = ax for simplicity
z(z) = a(ax) = a^2x
let a^2x = 1/16x and solve for a </span>
(i just changed my answer)
sqrt is the square root of
v=sqrt(2(ke)/m)
“C” Os the correct answer
Judging by the question I noticed that I can simplify the equation 3x-x+2=12 by one step.
The outcome of simplification should be 2x+2=12.
Next you must subtract 2 from both sides to isolate the x. The new equation should be 2x = 10.
Lastly you must divide both sides by 2, the answer you should get is x=5, D.
