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2 years ago

An expression of 40%

Mathematics

1 answer:

Marina86 [1]2 years ago

5 0

Not sure what you're asking, but if it's a T/F question, the answer would be false.

Hope this helped, and if it did I'd appreciate if you marked me as brainliest as I need it to get to a higher rank.

Read more on Brainly.com - brainly.com/question/5761136#readmore

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Solving multistep equations<br><br>6-2n=-4n-2-8

Vladimir [108]

<h3>Given Equation:</h3>

6 - 2n = -4n - 2 - 8

The value of n.

<h3>Solution:</h3>

6 - 2n = -4n - 2 - 8

or, -2n + 4n = -2 - 8 - 6

or, 2n = -16

or, n = -16/2

or, n = -8

<h2>Answer:</h2>

The value of n is -8.

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2 years ago

A circular field has a area of 14400 sq ft <br> What is the diameter of the field?

Bingel [31]

Answer:

240/sqrt(pi)

Step-by-step explanation:

We know that the area of a circle is $pi*r^2$, and we also know that the diameter of a circle is equal to $2r$.

Let's first make an equation for this problem.

pi*r^2=14400

Dividing both sides by pi, we get

r^2=14400/pi

Now, taking the square root of both sides gives us

r=120/sqrt(pi)

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Thus, we multiply the equation by two.

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3 years ago

HELP ASAP!!!!! Given: Point B is on the perpendicular bisector of AC¯¯¯¯¯. BD¯¯¯¯¯ bisects AC¯¯¯¯¯ at point D. Prove: B is equid

Harlamova29_29 [7]

Answer: Missing parts are,

In first blank, $AD\cong DC$ ,

In second blank, SAS postulate

In third blank, CPCTC postulate

Step-by-step explanation:

Since, Here D is the mid point on the line segment AC.

And BD is a perpendicular to the line AC.

Therefore, In triangles ADB and CDB ( shown in figure)

AD\cong DC ( By the definition of mid point)

$\angle BDA\cong \angle BDC$ ( right angles )

$BD\cong BD$ ( reflexive)

Thus, By SAS ( side angle side )postulate,

$\triangle ADB\cong \triangle CDB$

So, by CPCTC( Corresponding parts of congruent triangles are congruent)

$AB\cong CB$

Now, By definition of congruent segment,

AB=CB

By definition of equidistant,

B is equally far from both A and C.

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2 years ago

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