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zaharov [31]
3 years ago
9

1 question geometry :) thanks if you help

Mathematics
1 answer:
Inessa05 [86]3 years ago
3 0

Step-by-step explanation:

II will be the 90° clockwise rotation,

III will be the translation

IV will be the 180° rotation

V will be the 90° counter clockwise rotation

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Solve for P:<br><br> 9(p−4)=−18<br><br> Please Explain
vekshin1

Answer:

<em>p</em> = 2

Step-by-step explanation:

Happy to help.

When we have numbers in parenthesis, we generally want to deal with those first. However, we can hit a rough patch when a variable is in there. Consider this:

2(3 + 4) = 2(7), or 14.

But, the two can also be distributed into both numbers in the parenthesis, like this:

2(3 + 4) = 2*3 + 2*4

That leaves us with the same answer—14! We can apply this to a variable, and that will help us figure out 9(<em>p</em> - 4), or the left side of your equation you presented.

9(<em>p</em> - 4) = -18

9*<em>p</em> - 9*4 = -18

9<em>p</em> - 36 = -18

Add 36 on both sides to isolate the variable (in this case, <em>p)</em>

9<em>p</em> = -18 + 36

You can also write it like this; 9<em>p</em> = 36 - 18

9<em>p</em> = 18

Divide 9 to isolate <em>p</em>

<em>p</em> = 2

So, we would get (<em>p</em> = 2). Make sure to practice a few more questions like these to really get the hang of it—you'll be using this a lot in the future!

Good luck!

3 0
3 years ago
Find the perimeter of the sector of a circle of radius 14cm with an angle of 72 degree
Alika [10]

Answer:

the area sector is 123.2

7 0
3 years ago
PLEASE HELP!!! ILL GIVE BRAINLIEST, EXPLAIN YOUR ANSWER PLEASE
mart [117]

Answer: -20v^3 - 30x^2 +20

Step-by-step explanation:

simply multiply each term inside of the parentheses by -5.

4 0
3 years ago
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A population has a standard deviation of 5.5. What is the standard error of the sampling distribution if the sample size is 81?
VladimirAG [237]

Answer:

\sigma = 5.5

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution \bar X and for this case we know that the distribution is given by:

\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})

And the standard error would be:

\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}

And replacing we got:

\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611

Step-by-step explanation:

For this case we know the population deviation given by:

\sigma = 5.5

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution \bar X and for this case we know that the distribution is given by:

\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})

And the standard error would be:

\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}

And replacing we got:

\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611

4 0
3 years ago
Which line plot shows the data?
Bogdan [553]

Answer:

I think its b

Step-by-step explanation:

Dont shoot the messenger that's just my best Interpretation

8 0
3 years ago
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