pretty much about the same as before.
a = weight of a large box
b = weight of a small box.
we know their combined weight is 65 lbs, thus a + b = 65.
we also know that the truck has 60 large ones, and 55 small ones, thus 60*a is the total weight for the large ones and 55*b is the total weight for the small ones, and we know that is a total of 3775, 60a + 55b = 3775.

Answer:
The probability that a part was manufactured on machine A is 0.3
Step-by-step explanation:
Consider the provided information.
It is given that Half of a set of parts are manufactured by machine A and half by machine B.
P(A)=0.5
Let d represents the probability that part is defective.
Ten percent of all the parts are defective.
P(d) = 0.10
Six percent of the parts manufactured on machine A are defective.
P(d|A)=0.06
Now we need to find the probability that a part was manufactured on machine A, and given that the part is defective
:



Hence, the probability that a part was manufactured on machine A is 0.3
All your doing here is 37-19 adding negative is the same has munising
So 37-19=18
3 + 5(c + 3) = -17
First, subtract 3 from both sides. / Your problem should look like:
Second, simplify -17 - 3 to get -20. / Your problem should look like:
Third, divide both sides by 5. / Your problem should look like:
Fourth, simplify

to 4. / Your problem should look like:
Fifth, subtract 3 from both sides. / Your problem should look like:
Sixth, simplify -4 - 3 to get -7. / Your problem should look like:

Answer:
c = -7
(30/100)(90*3+50*4)
(30/100)(270+200)
(30/100)(470)
$141.00