X=width of a coccer pitch
2x-20=length of a soccer pitch
Area (rectangule)=length x width
We suggest this equation:
x(2x-20)=6000
2x²-20x=6000
2x²-20x-6000=0
x²-10x-3000=0
We solve this quadratic equation:
x=[10⁺₋√(100-4*1*-3000)]/2=[10⁺₋√(100+12000)]/2=
=(10⁺₋110)/2
we have two solutions:
x₁=(10-110)/2=-50, invalid solution.
x₂=(10+110)/2=60
x=60
2x-20=2(60)-20=120-20=100
Solution: the length is 100 m, and the width is 60 m.
To check:
Area=100 m*60 m=6000 m²
The twice of width is =2(60 m)=120 m,
20 m less than twice its width is: 120 m-20 m=100 m=the length.
She had $100 and she gave $3 to her sister so $10-$3=$7 and her parent quadrupled her remaining dollars which was $7 so $7x4=$28 the answer is $28
Answer:
Queen spends 1 1/1 less time at studying.
Hi there!
345*28923+808(2829)
The first step put the problem into 2 parts, the first part is 345*28923
The second part is 808(2829)
The parentheses means to multiply that number that it touches.
Add the final 2 answers.
345*28923 = 9,978,435
808(2829) = 2,285,832
Now, add the answers.
9,978,435 + 2,285,832 = 12,264,267
Hope this helped!~
Calculate the number of people who sat on the visitors' side:
8644
-5100
--------
3544
Now divide 3544 people by 8 sections:
3544 people
----------------- = 443 per section.
8 sections
