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Thepotemich [5.8K]
3 years ago
11

How many groups of sixty are in 244

Mathematics
1 answer:
finlep [7]3 years ago
3 0
4 would be the answer
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(Mhanifa) please solve this question thank you!
ivanzaharov [21]

Answer:

  • Option A

Step-by-step explanation:

A'B' is 1/2 times the AB as the scale factor is 1/2.

<u>Find the length of AB using distance formula.</u>

  • AB = \sqrt{(4 - 2)^2 + (4-0)^2}  = \sqrt{20}  = 2\sqrt{5}

<u>And find A'B':</u>

  • A'B' = 1/2*2\sqrt{5}  = \sqrt{5}

Correct choice is A

8 0
3 years ago
Find the x-intercepts of f(x) = x2 + 7x + 10.
Andrej [43]

Answer:

x = - 5, x = - 2

Step-by-step explanation:

Given

f(x) = x² + 7x + 10

To find the x- intercepts let f(x) = 0, that is

x² + 7x + 10 = 0 ← in standard form

(x + 2)(x + 5) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 2 = 0 ⇒ x = - 2

x + 5 = 0 ⇒ x = - 5

The x- intercepts are (- 5, 0) and (- 2, 0 )

6 0
3 years ago
Elijah put 2x+3 dollars in the bank the first week. The following week he doubled the first week’s savings and put that amount i
ella [17]

I believe the answer would be $79.50.

7 0
3 years ago
In June, Tara gathered data about amusement park attendance on days with different temperatures. Tara used the equation y=−3.5x+
sergij07 [2.7K]

Answer:

25

Step-by-step explanation:

Given the model:

y=−3.5x+400

Number of children in amusement park = y

Temperature = x

On a certain day:

Temperature = 90°F

Number of children in park = 60

Using the model :

The predicted number of children in park when temperature is 90°F would be :

y = - 3.5(90) + 400

y = - 315 + 400

y = 85

Model prediction = 85 children

Actual figure = 60

Residual :

|Actual - predicted | = |60 - 85| = 25 children

6 0
3 years ago
Juan always saves the same amount from his weekly allowance. The table shows how much he has saved at different times.
erastova [34]
On the 14 week Juan will save $ 52 because each 3 week he earns 3.
So you do 9 divide by 3 and get 3. Then you do 3 times 2 and get 6.
46 + 6 = 52
~JZ
4 0
3 years ago
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