Complete the square to determine the minimum or maximum value of the function defined by the expression.

The growing interest in and use of the Internet have forced many companies into considering ways to sell their products on the W

Romashka [77]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data:

Education : 11 11 8 13 17 11 11 11 19 13 15 9 15 15 11

Internet use 10 5 0 14 24 0 15 12 20 10 5 8 12 15 0

Labeled scatter plot of Education and Internet Use is attached in the picture below.

Yes there appears to be a linear relationship between the two variables (Education and Internet Use) as the data points appears to have an upward trend depicted by the linear trend line in the graph.

The correlation Coefficient value which is measures the degree of linear relationship between education and internet use is 0.7048

4 0

3 years ago

The basketball coach make up a game to play where each game takes. 10 shots at the basket. For every basket made, the player gai

levacccp [35]

Answer:

5s + 5m

5(10) + 5(-15)

50 - 75 = -25 points

Step-by-step explanation:

s = sanked baskets = 10

m = missed baskets = -15

7 0

3 years ago

Bill has lost 40 pounds in 8 weeks. What is his weekly rate?

choli [55]

Answer:

5 pounds

Step-by-step explanation:

40 divided by 8 = 5

6 0

3 years ago

Read 2 more answers

1. If a side started out with a side length of 11 and ended with a side length of 71 what is the dilation's scale factor? Write

jeka57 [31]

Regarding dilation, it is found that:

1. The scale factor is of 6.45

2. The scale factor is of 1.4375.

3. the image will be smaller than the pre-image.

<h3>Dilation</h3>

A dilation is one type of transformation that is applied to images, in which the side lengths are multiplied by a constant called scale factor, changing the side lengths of the image.

In item a, the initial length was of 11 and the final length is of 71, hence the multiplier, which is the scale factor, is given as follows:

71/11 = 6.45.

In item b, the initial length was of 16 and the final length was of 23, hence the scale factor is given as follows:

23/16 = 1.4375.

For item 3, the multiplier is a number that is less than 1, meaning that the image is smaller than the pre-image.

More can be learned about dilation at brainly.com/question/3457976

#SPJ1

6 0

1 year ago

4 Tan A/1-Tan^4=Tan2A + Sin2A

Eva8 [605]

tan(2A) + sin(2A) = sin(2A)/cos(2A) + sin(2A)

• rewrite tan = sin/cos

… = 1/cos(2A) (sin(2A) + sin(2A) cos(2A))

• expand the functions of 2A using the double angle identities

… = 2/(2 cos²(A) - 1) (sin(A) cos(A) + sin(A) cos(A) (cos²(A) - sin²(A)))

• factor out sin(A) cos(A)

… = 2 sin(A) cos(A)/(2 cos²(A) - 1) (1 + cos²(A) - sin²(A))

• simplify the last factor using the Pythagorean identity, 1 - sin²(A) = cos²(A)

… = 2 sin(A) cos(A)/(2 cos²(A) - 1) (2 cos²(A))

• rearrange terms in the product

… = 2 sin(A) cos(A) (2 cos²(A))/(2 cos²(A) - 1)

• combine the factors of 2 in the numerator to get 4, and divide through the rightmost product by cos²(A)

… = 4 sin(A) cos(A) / (2 - 1/cos²(A))

• rewrite cos = 1/sec, i.e. sec = 1/cos

… = 4 sin(A) cos(A) / (2 - sec²(A))

• divide through again by cos²(A)

… = (4 sin(A)/cos(A)) / (2/cos²(A) - sec²(A)/cos²(A))

• rewrite sin/cos = tan and 1/cos = sec

… = 4 tan(A) / (2 sec²(A) - sec⁴(A))

• factor out sec²(A) in the denominator

… = 4 tan(A) / (sec²(A) (2 - sec²(A)))

• rewrite using the Pythagorean identity, sec²(A) = 1 + tan²(A)

… = 4 tan(A) / ((1 + tan²(A)) (2 - (1 + tan²(A))))

• simplify

… = 4 tan(A) / ((1 + tan²(A)) (1 - tan²(A)))

• condense the denominator as the difference of squares

… = 4 tan(A) / (1 - tan⁴(A))

(Note that some of these steps are optional or can be done simultaneously)

7 0

3 years ago