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klemol [59]
3 years ago
5

For an angle θ, tan(θ) is a negative number. Which quadrants might θ be in?

Mathematics
2 answers:
Norma-Jean [14]3 years ago
6 0

θ will be in <u>quadrants II and IV</u> for an angle θ, tan(θ) is a negative number.

Hope it helps.

Klio2033 [76]3 years ago
4 0

So for this question, we're asked to find the quadrant in which the angle of data lies and were given to conditions were given. Sign of data is less than zero, and we're given that tangent of data is also less than zero. Now I have an acronym to remember which Trig functions air positive in each quadrant. . And in the first quadrant we have that all the trig functions are positive. In the second quadrant, we have that sign and co seeking are positive. And the third quadrant we have tangent and co tangent are positive. And in the final quadrant, Fourth Quadrant we have co sign and seeking are positive. So our first condition says the sign of data is less than zero. Of course, that means it's negative, so it cannot be quadrant one or quadrant two. It can't be those because here in Quadrant one, we have that all the trick functions air positive and the second quadrant we have that sign. If data is a positive, so we're between Squadron three and quadrant four now. The second condition says the tangent of data is also less than zero now in Quadrant three. We have that tangent of data is positive, so it cannot be quadrant three, so our r final answer is quadrant four, where co sign and seek in are positive.  

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Answer:

Solution given:

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a What is the slope of a line parallel to it?

Since for parallel slope are equal ,

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Since for perpendicular line slope is reciprocal to another line but negative so

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2 years ago
Unit Test 4
o-na [289]

Answer:

C. 30

Step-by-step explanation:

circumference of the semicircular plot

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3 years ago
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7 0
3 years ago
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4 0
3 years ago
suppose a study estimated the population mean for a variable of interest using a 99% confidence interval. If the width of the es
Dovator [93]

Answer:

Population standard deviation, \sigma = 3683.063 .

Step-by-step explanation:

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We know that Width of confidence interval = 2 * Margin of error

<em> Margin of error</em><em> </em>= Z_\frac{\alpha}{2} * \frac{\sigma}{\sqrt{n} } = 2.5758 * \frac{\sigma}{\sqrt{1000} } {because at 1% significance level

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Therefore,  600 = 2 * 2.5758 * \frac{\sigma}{\sqrt{1000} }

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Hence, the Population standard deviation = 3683.063 .

7 0
3 years ago
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