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Juli2301 [7.4K]
3 years ago
12

A conical-shaped umbrella has a radius of 0.4 m and a height of 0.45 m. Calculate the amount of fabric needed to manufacture thi

s umbrella. (Hint: an umbrella will have no base)
Mathematics
1 answer:
bonufazy [111]3 years ago
7 0

Answer:

The correct answer will be "0.756596 m²".

Step-by-step explanation:

The given values are:

The radius of an umbrella,

r = 0.4 m

The height of an umbrella,

h = 0.45 m

As we know,

The lateral surface of an umbrella will be:

⇒  \pi r\sqrt{r^2+h^2}

On substituting the values, we get

⇒  \pi \times 0.4\sqrt{(0.4)^2=(0.45)^2}

⇒  0.756596 \ m^2

So that the amount of fabric needed will be "0.756596 m²".

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Answer:

The fraction 1/4 is a rational number.

It stands for the ratio between the integers 1 and 4.

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describe the steps you would take to determine the distance in miles between two towns that are 200 kilometers apart
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It will be -200 kilometers because you gotta get a ruler
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The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 30,393 miles, with a standard
Pie

Answer:

52.84% probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem:

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 30393, \sigma = 2876, n = 37, s = \frac{2876}{\sqrt{37}} = 472.81

What is the probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

This probability is the pvalue of Z when X = 30393 + 339 = 30732 subtracted by the pvalue of Z when X = 30393 - 339 = 30054. So

X = 30732

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{30732 - 30393}{472.81}

Z = 0.72

Z = 0.72 has a pvalue of 0.7642.

X = 30054

Z = \frac{X - \mu}{s}

Z = \frac{30054 - 30393}{472.81}

Z = -0.72

Z = -0.72 has a pvalue of 0.2358

0.7642 - 0.2358 = 0.5284

52.84% probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

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Answer:

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Hall A Total Cost

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