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AVprozaik [17]
3 years ago
11

14 The straight line, L, has the equation y = 5 - 2x

Mathematics
1 answer:
lozanna [386]3 years ago
7 0

Answer:

Step-by-step explanation:

(a) the co-ordinates of the point where the line crosses the y-axis,

y intercept occurs when x = 0

y = 5 - 2(0)

y = 5

(0, 5)

(b) the gradient of the line,

the general line formula is y = mx + b, where m is the slope and b is the y intercept.

y = 5 - 2x

y = -2x + 5

m = -2

(c) the equation of a line parallel to L.

Parallel lines have the same slope, but different y intercepts.

The simplest parallel line formula is

y = -2x + 0

y = -2x

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Simplify the square root of 3 times the fifth root of 3.
bogdanovich [222]

Answer:

<h2><em>Three to the three fifths power.</em></h2>

Step-by-step explanation:

The given expression is

\sqrt{3\sqrt[5]{3} }

To simplify this expression, we have to use a specific power property which allow us to transform a root into a power with a fractional exponent, the property states:

\sqrt[n]{x^{m}}=x^{\frac{m}{n}}

Applying the property, we have:

\sqrt{3\sqrt[5]{3}}=\sqrt{3(3)^{\frac{1}{5}}}=(3(3)^{\frac{1}{5}})^{\frac{1}{2}}

Now, we multiply exponents:

(3(3)^{\frac{1}{5}})^{\frac{1}{2}}\\3^{\frac{1}{2}}3^{\frac{1}{10}}

Then, we sum exponents to get the simplest form:

3^{\frac{1}{2}}3^{\frac{1}{10}}=3^{\frac{1}{2}+\frac{1}{10}} =3^{\frac{10+2}{20}}=3^{\frac{12}{20}}  \\\therefore \sqrt{3\sqrt[5]{3}}=3^{\frac{3}{5} }

Therefore, the right answer is <em>three to the three fifths power.</em>

3 0
3 years ago
Read 2 more answers
Indicate which two quadrants “theta” could terminate if sin theta = 4/5
Nitella [24]

Answer:

1st and 2nd quadrants

Step-by-step explanation:

You have sine is positive since it is 4/5.

Sine is the y-coordinate.

On the coordinate plane y is positive in the 1st and 2nd quadrants.

8 0
3 years ago
What is the distributive property of -4 (10-b)
brilliants [131]

Answer:

-40+4b

Step-by-step explanation:

You multiply the outside (-4) by the things within the parentheses

6 0
2 years ago
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What is the range of the function f(x) = 2 – 2 when the domain is {0, 2, 4}? O {-1, 2, 14} {3, 6, 8} {-2, 2, 6) All real numbers
devlian [24]

Answer:

F = 0

Step-by-step explanation:

F(x) = 2 - 2

fx/3 = 0/x

f=0

5 0
3 years ago
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For the given values of n and d, find integers q and r such that n = dq + r and 0 ≤ r &lt; d. n = −67, d = 8
Firlakuza [10]

Answer:

q = 8

r = 3

Step-by-step explanation:

Given

n = dq + r

0 \le r < d

n = 67 --- not -67

d = 8

Required

Find q and r

Substitute values for d and b

n = dq + r

67 = 8 * q + r

67 = 8q + r

Make q the subject

q = \frac{67 - r}{8}

0 \le r < d means that r is less than 8 but greater than or equal to 0

And r and q are integers.

Let r = 3

q = \frac{67 - 3}{8}

q = \frac{64}{8}

q = 8

No other true values of r and q can be gotten.

7 0
3 years ago
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