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2 years ago

14 The straight line, L, has the equation y = 5 - 2x

Mathematics

1 answer:

lozanna [386]2 years ago

7 0

Answer:

Step-by-step explanation:

(a) the co-ordinates of the point where the line crosses the y-axis,

y intercept occurs when x = 0

y = 5 - 2(0)

y = 5

(0, 5)

(b) the gradient of the line,

the general line formula is y = mx + b, where m is the slope and b is the y intercept.

y = 5 - 2x

y = -2x + 5

m = -2

(c) the equation of a line parallel to L.

Parallel lines have the same slope, but different y intercepts.

The simplest parallel line formula is

y = -2x + 0

y = -2x

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Delvig [45]

Here is your answer

Money saved on each successive day is-

$3, &5, $7....

Clearly it forms an AP,

where

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common difference, d= 2

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using formula

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Write an equation of a line in slope-intercept form that passes through (-3,5) and is parallel to y = -6x +1.

katrin2010 [14]

Answer:

a) The equation of the Parallel line to the given straight line is

6 x + y + 13 =0

b) Slope - intercept form

y = - 6 x - 13

c) The intercept - form

$\frac{x}{\frac{-13}{6} } + \frac{y}{-13} = 1$

x - intercept = $\frac{-13}{6}$

y - intercept = - 13

Step-by-step explanation:

Step(i):-

Given the equation of the straight line

y = -6x +1

6 x + y - 1 = 0

The equation of the Parallel line to the given straight line is

6x + y + k=0 and it passes through the point (-3, 5 )

⇒ 6 (-3 ) + 5 + k =0

⇒ - 18 + 5 + k=0

⇒ -13 + k = 0

⇒ k = 13

The equation of the Parallel line to the given straight line is

6 x + y + 13 =0

Step(ii):-

Slope - intercept form

y = m x + C

y = - 6 x - 13

Step(iii):-

Intercept - form

6 x + y + 13 =0

6 x + y = - 13

$\frac{6x + y}{-13} = \frac{-13}{-13}$

$\frac{6x}{-13} + \frac{y}{-13} = 1$

$\frac{x}{\frac{-13}{6} } + \frac{y}{-13} = 1$

The intercept - form

$\frac{x}{\frac{-13}{6} } + \frac{y}{-13} = 1$

x - intercept = $\frac{-13}{6}$

y - intercept = - 13

4 0

2 years ago