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N76 [4]
3 years ago
9

Which number is between 1/7 and 0.2

Mathematics
2 answers:
ololo11 [35]3 years ago
3 0
0.2 is 1/5 so the number between 1/7 and 1/5 so the ANSWER is 1/6
djyliett [7]3 years ago
3 0

let's convert the 0.2 to a fraction, and then let's put them both fractions using the same denominator.


we can convert any decimal by simply "using a denominator with as many zeros as there are decimals", so 0.2 has 1 decimal, so we use one zero, let's proceed,


\bf 0.\underline{2}\implies \cfrac{02}{1\underline{0}}\implies \stackrel{simplified}{\cfrac{1}{5}}


now, to put those two fractions with the same denominator, we simply "multiply each other by the other's denominator", let's see how that goes,


\bf \stackrel{\textit{we multiply top and bottom by 5}}{\cfrac{1}{7}\implies \cfrac{1\cdot 5}{7\cdot 5}\implies \cfrac{5}{35}}\qquad \qquad \qquad \stackrel{\textit{we multiply top and bottom by 7}}{\cfrac{1}{5}\implies \cfrac{1\cdot 7}{5\cdot 7}\implies \cfrac{7}{35}} \\\\\\ ~~~~~~~~~~\boxed{\cfrac{5}{35}}\text{\textemdash\textemdash\textemdash\textemdash\textemdash\textemdash\textemdash}\cfrac{6}{35}\text{\textemdash\textemdash\textemdash\textemdash\textemdash\textemdash\textemdash}\boxed{\cfrac{7}{35}}

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If f(x)=x^3-12x^2+35x-24f(x)=x 3 −12x 2 +35x−24 and f(8)=0f(8)=0, then find all of the zeros of f(x)f(x) algebraically.
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Answer:

The zeros of f(x) are: (x - 1), (x - 3) and (x - 8)

<em></em>

Step-by-step explanation:

Given

f(x)=x^3-12x^2+35x-24

f(8) = 0

Required

Find all zeros of the f(x)

If f(8) = 0 then:

x = 8

And x - 8 is a factor

Divide f(x) by x - 8

\frac{f(x)}{x - 8} = \frac{x^3-12x^2+35x-24}{x - 8}

Expand the numerator

\frac{f(x)}{x - 8} = \frac{x^3 - 4x^2 -8x^2 + 3x + 32x - 24}{x - 8}

Rewrite as:

\frac{f(x)}{x - 8} = \frac{x^3 - 4x^2 + 3x - 8x^2 +32x - 24}{x - 8}

Factorize

\frac{f(x)}{x - 8} = \frac{(x^2 - 4x + 3)(x - 8)}{x - 8}

Expand

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Factorize

\frac{f(x)}{x - 8} = \frac{(x - 1)(x - 3)(x - 8)}{x - 8}

\frac{f(x)}{x - 8} = (x - 1)(x - 3)

Multiply both sides by x - 8

f(x) = (x - 1)(x - 3)(x - 8)

<em>Hence, the zeros of f(x) are: (x - 1), (x - 3) and (x - 8)</em>

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