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3 years ago

8

State the domain and range for the following relation. {(-4,4), (1, 2), (0, 3), (3, 2)}

1 answer:

Andreas93 [3]3 years ago

5 0

Answer:

Step-by-step explanation:

D= {-4,1,0,3}

R={4,2,3,2}

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DaniilM [7]

Answer:

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Step-by-step explanation:

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3 years ago

Nicole plans to watch 3 movies each month . Write an equation to represent the total number of movies n that she will watch in m

kramer

N=3x, x is months and n is the total.

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3 years ago

Identify the perfect cube contained as a factor in 54

erastova [34]

Answer:

27.

Step-by-step explanation:

54 = 2 * 3 * 3 * 3.

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8 0

3 years ago

Order these numbers from least to greatest. −270 , 16310 , −503 , −16.5

pychu [463]

-503,-270,-16.5,16310

8 0

3 years ago

Consider the equation below.

Korvikt [17]

Answer:

Equation in square form:

$y=3(x+5)^2-4$

Extreme value:

$(h,k)=(-5,-4)$

Step-by-step explanation:

We are given

$y=3x^2+30x+71$

we can complete square

$y=3(x^2+10x)+71$

we can use formula

$a^2+2ab+b^2=(a+b)^2$

$y=3(x^2+2\times x\times 5)+71$

now, we can add and subtract 5^2

$y=3(x^2+2\times x\times 5+5^2-5^2)+71$

$y=3(x^2+2\times x\times 5+5^2)-3\times 5^2+71$

$y=3(x+5)^2-75+71$

So, we get equation as

$y=3(x+5)^2-4$

Extreme values:

we know that this parabola

and vertex of parabola always at extreme values

so, we can compare it with

$y=a(x-h)^2+k$

where

vertex=(h,k)

now, we can compare and find h and k

$y=3(x+5)^2-4$

we get

h=-5

k=-4

so, extreme value of this equation is

$(h,k)=(-5,-4)$

6 0

3 years ago

Read 2 more answers