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jeyben [28]
3 years ago
9

27 miles per hour. how many miles per minute in decimal form?

Mathematics
1 answer:
maxonik [38]3 years ago
7 0

1 hour = 60 minutes

27/60 = 0.45 miles per minute

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Find equation of the line passing through(0,-3),which has a gradient of 2
WINSTONCH [101]

Answer:

y = 2x - 3

Step-by-step explanation:

y - - 3 = 2(x-0)

y + 3 = 2x

y = 2x -3

7 0
2 years ago
Read the paragraph below. Which would be the most helpful peer review comment to make about the writer’s style?
sasho [114]

Answer:

“I think wolves are scary, too. You’ll have to do more to convince me that they’re not!”

Step-by-step explanation:

5 0
1 year ago
Find the missing dimension of each triangle described height 14 inches area 245 inches Square
Amiraneli [1.4K]
Given:
Triangle 
height 14 inches
area 245 inches square

Formula in finding the area of a triangle is:

Area = (height * base) / 2

The base is missing, so we need to compute its value using the given figures.

245 = (14 * b) / 2
245 * 2 = 14b
490 = 14b
490/14 = b
35 = b

The base is 35 inches.
4 0
3 years ago
A homeowner has an octagonal gazebo inside a circular area. Each vertex of the gazebo lies on the circumference of the circular
Tcecarenko [31]

If we draw the diagonals of the octagonal gazebo, the 4 diagonals divide the octagon into 8 triangles.

Note that each triangle is an isosceles triangle whose equal sides are x, the radius of the circle.

The top angle of each triangle is obtained by dividing the full angle by 8.

So, each top angle = \frac{360}{8}

= 45°

Now, in fig., consider one of the triangles Δ OAB. Draw an altitude OC from O to the opposite side AB.

This altitude OC bisects the top angle 45°.

Therefore, ∠ AOC = 22.5°.

Now, in Δ AOC,

sin 22.5=\frac{AC}{OA}

=\frac{AC}{x}

So, AC = x sin 22.5°

Note that, AB = 2 AC.

Therefore, AB = 2x sin 22.5°.

Also, cos 22.5=\frac{OC}{OA}

=\frac{OC}{x}

So, OC = x cos 22.5°.

Area of Δ AOB = \frac{1}{2}(AB)(OC)

= \frac{1}{2} × (2x sin 22.5°) × (x cos 22.5°)

= \frac{1}{2} x^{2} (2 sin 22.5° cos 22.5°)

= \frac{1}{2} x^{2} sin 45°

= x^{2} / 2\sqrt{2}

Area of the octagonal gazebo = 8 × one triangular area

= 8 × (x^{2} / 2\sqrt{2})

=2\sqrt{2} x^{2}

=2.828x^{2}

Area required for mulch = circular area - area of the gazebo

=3.14x^{2} -2.828x^{2}

=0.312x^{2}

Now, cost per unit area = $1.50.

Hence, total cost g(m) = area × cost per unit area

Total cost g(m) = 0.312x^{2} × 1.5

=0.468x^{2}

Hence, total cost g(m) = 0.468x^{2}.

4 0
3 years ago
5 / 4 x + 3 = x - 1 / 4
tiny-mole [99]
5/4x+3 = x-1/4
5/4x-x = -1/4-3
1/4x = -13/4
x = -13/4.4
x = - 13
6 0
3 years ago
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