Answer:
The dependent variable for this experiment is the ability of students with similar intellectual abilities to recall the meaning of a symbol in a textbook one week after the start of the experiment which depends on the presence or absence of noise outside the classroom.
Step-by-step explanation:
In an experiment, the independent variable is the one whose value, form or outcome is not determined by any other variable in the experiment.
The dependent variable is the one whose value, form or outcome is determined by one or more other variable(s) in the experiment.
This experiment tests the abilities of students with similar intellectual abilities to recall the meaning of a symbol in a textbook one week after the start of the experiment.
This ability was made to depend on whether there was noise or no noise outside their classrooms.
Since, this variable to be measured is determined by another variable in the experiment, it is evident that this is the dependent variable for this experiment.
Hope this Helps!!!
Check the picture below, so the hyperbola looks more or less like so, so let's find the length of the conjugate axis, or namely let's find the "b" component.
![\textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2} \end{cases} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Ctextit%7Bhyperbolas%2C%20horizontal%20traverse%20axis%20%7D%20%5C%5C%5C%5C%20%5Ccfrac%7B%28x-%20h%29%5E2%7D%7B%20a%5E2%7D-%5Ccfrac%7B%28y-%20k%29%5E2%7D%7B%20b%5E2%7D%3D1%20%5Cqquad%20%5Cbegin%7Bcases%7D%20center%5C%20%28%20h%2C%20k%29%5C%5C%20vertices%5C%20%28%20h%5Cpm%20a%2C%20k%29%5C%5C%20c%3D%5Ctextit%7Bdistance%20from%7D%5C%5C%20%5Cqquad%20%5Ctextit%7Bcenter%20to%20foci%7D%5C%5C%20%5Cqquad%20%5Csqrt%7B%20a%20%5E2%20%2B%20b%20%5E2%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
Answer: what what! Confused
Step-by-step explanation:
Answer:
please the answer is the third option
A locker requires a three-digit code to open the lock. The code must contain one letter and two numbers, and no letter or number can be repeated. You can choose from among four letters, A, B, C, and D, and two numbers, 5 and 6.
The size of the sample space is: (8, 16, 20, 24)
If a code is chosen at random, the probability that it has a letter that immediately follows an odd number is: (1/8, 1/6, 1/3, 2/5, 2/3)
If a code is chosen at random, the probability that D is in the code but is not in the first position is: (1/8, 1/6, 1/3, 2/5, 2/3)
