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brilliants [131]
2 years ago
7

Of the 48 oranges in a carton 1/3 of them were rotten Ben and David took the remaining good oranges it's been took eat my orange

s and David how many oranges did David take
Mathematics
1 answer:
Burka [1]2 years ago
8 0

Answer:

David took 16 oranges.

Step-by-step explanation:

We are given the following in the question:

Total number of oranges = 48

Oranges rotten =

\dfrac{1}{3}

Number of oranges rotten =

\dfrac{1}{3}\times 48\\\\=16

There were 16 rotten oranges.

Number of good oranges left =

= 48-16\\=32

These are equally divided among Ben and David.

Number of oranges each Ben and David get =

\dfrac{32}{2} = 16

Thus, David took 16 oranges.

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2 years ago
A.) name the solutions for the quadratic function graphed
vladimir2022 [97]
(0, -5) and (0, 3)
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2 years ago
You have two dollars and 50 Cent the gumballs in the machine cost $.25 each right and solve an inequality represents the number
vladimir2022 [97]

Answer:

The maximum number of gumballs you can buy is 10

Step-by-step explanation:

Let

x ---->represents the number of gumballs you can buy

we know that

The number of gumballs you can buy multiplied by it cost must be less than or equal to $2.50 (two dollars and 50 cents)

so

The inequality that represent this situation is

0.25x\leq 2.50

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The maximum number of gumballs you can buy is 10

5 0
3 years ago
The difference between the roots of the quadratic equation x^2−14x+q=0 is 6. Find q.
pychu [463]

Answer :

The value of q for, the given quadratic equation is 40

Step-by-step explanation :

Given quadratic equation as :

x² - 14 x + q = 0

And  , Difference between the roots of equation is 6

Let A , B be the roots of the equation

So, A - B = 6

The roots of the quadratic equation  ax² + bx + c = 0 as can be find as :

x = \frac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}

x = \frac{14\pm \sqrt{(-14)^{2}-4\times 1\times q}}{2\times 1}

or, x = \frac{-14\pm \sqrt{196-4 q}}{2}

Or, x = \frac{-14\pm \sqrt{196-4 q}}{2}

So , The roots are

A = -7 + \frac{\sqrt{196-4q}}{2}

And B = -7 - \frac{\sqrt{196-4q}}{2}

∵ The difference between the roots is 6

So, A - B = 6

Or, ( -7 + \frac{\sqrt{196-4q}}{2} ) - (  -7 - \frac{\sqrt{196-4q}}{2} ) = 6

Or, ( - 7 + 7 ) + 2 ( \sqrt{196-4q} = 6

Or, 0 + 2 ( \sqrt{196-4q} = 6

∴ 196 - 4 q = 36

or, 4 q = 196 - 36

or 4 q = 160

∴ q = \frac{160}{4}

I.e q = 40

S0, The value of q = 40

Hence The value of q for, the given quadratic equation is 40 . Answer

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2 years ago
I need help with 0.5(-12p - 4)
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Step-by-step explanation:

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3 years ago
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