$g(x)=4x-\dfrac{1}{4x}=4x-(4x)^{-1}\\\\\\\\g'(x)=\left[4x-(4x)^{-1}\right]'=(4x)'-\left[(4x)^{-1}\right]'=4-[-1(4x)^{-2}]\cdot4\\\\=4+\dfrac{1}{(4x)^2}\cdot4=4+\dfrac{4}{4^2x^2}=\boxed{4+\dfrac{1}{4x^2}}\\\\Used:\\\\(f(x)-g(x))'=f'(x)-g'(x)\\\\.[f(g(x))]'=f'(g(x))\cdot g'(x)\\\\(x^n)'=nx^{n-1}$

8 0

3 years ago

Answer?????????????????

ANTONII [103]

So the angle A on the first diamond corresponds with angle Q, angle B with angle S, angle C with angle R, and angle D with angle P. So if angle D correspond (equals) angle P then x+34=97 and if angle R corresponds with C then 3y-13=83. From there just do some basic algebra to find the x and y values.

5 0

4 years ago

Jada had read 2/3 of a book . She has read 60 pages so far . How many pages are in the whole book?

user100 [1]

90 pages in the whole book

3 0

3 years ago

Which formulas can be used to find the surface area of a right prism where p is the perimeter of the base, h is the height of th

svetoff [14.1K]

Answer:

SA=BA+LA and SA=BA+ph

Step-by-step explanation:

I just looked it up

6 0

3 years ago