The correct answer is E)52
When there is Hardy-Weinberg equilibrium like in this case of a single locus with two alleles denoted A and a with frequencies f(A) = p and f(a) = q, the expected genotype frequencies under random mating are f(AA) = p² for the AA homozygotes, f(aa) = q² for the aa homozygotes, and f(Aa) = 2pq for the heterozygotes. Let's put that A is dominant and a is recessive allele. In Hardy-Weinberg equilibrium we have:
p²+2*p*q+q²= 1 p+q=1 p=1-q
f(a) =0.4=q q²=0.4²=0.16=16%
p= 1-0.4=0.6 p²=0.6²=0.36=36%
Percentage of a homozygous genotype in the population is 16%+36%=52%
Based on the salient features and the laboratories of this patient, this is a case of Crohn's disease. Crohn's disease is type of chronic inflammatory bowel disease or IBD along with ulcerative colitis. Crohn's disease usually presents with diarrhea, abdominal pain, and significant weight loss. Pathologically, it is characterized by "skip-lesions" or discontinuous granulomatous that occurs on all layers of the bowel (transmural); with the involvement of the whole gastrointestinal tract. Patients with Crohn's disease have a significant risk in developing colorectal cancer.
Answer:
The answer is a.) Transform Boundary.
Answer:
The phase in which two haploid daughter cells are produced is telophase.
Explanation:
