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2 years ago

Need help!!!

Mathematics

2 answers:

Assoli18 [71]2 years ago

7 0

Answer:

73 mph during the second hour!

Step-by-step explanation:

Hour 1=54 mph

Hour 2=? mph

Hour 3=82 mph

Total=209 mph

this means that 209=82+54+?

Simplify it and you will get 73

73 mph

kvasek [131]2 years ago

6 0

Answer: 73

Step-by-step explanation:

Setting Up An Equation

The question provides the distances the train traveled in the first 3 hours

T = total distance

A = distance during 1st hour

B = distance during 2nd hour

C = distance during 3rd hour

the total distance traveled is equal to the sum of the distances of the first three hours so our equation would be

T = A + B + C

Solving For B

Since the question asks for the distance during the second hour, we need to find B

It is already given that A = 54, C = 82, and T = 209, so plug in the values and solve for B

T = A + B + C

B = T - A - C

B = 209 - 54 - 82

B = 73

Final Answer

B = 73

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Tell whether x and y show direct variation, inverse variation or - y/4 = 2x

Sophie [7]

9514 1404 393

Answer:

direct variation

Step-by-step explanation:

The given equation can be written in the direct variation form ...

y = kx

y = -8x . . . . rewrite of the given equation (multiply by -4)

This is an example of direct variation.

4 0

2 years ago

Find the 10th partial sum of the arithmetic sequence defined by

Evgesh-ka [11]

Answer:

22.5

Step-by-step explanation:

If you expand the series, you can see the first few terms of the series:

Putting 1 in $n$ , $\frac{1}{2}(1)-\frac{1}{2}=0$
Putting 2 in $n$ , $\frac{1}{2}(2)-\frac{1}{2}=0.5$
Putting 3 in $n$ , $\frac{1}{2}(3)-\frac{1}{2}=1$
Putting 4 in $n$ , $\frac{1}{2}(4)-\frac{1}{2}=1.5$

We can see the series is 0, 0.5, 1, 1.5, ....

This is an arithmetic series with common difference (the difference in 2 terms) 0.5 and first term 0.

We know formula for sum of arithmetic series:

$s_{n}=\frac{n}{2}(2a+(n-1)d)$

Where,

$S_{n}$ denotes the nth partial sum
$a$ is the first term (in our case it is 0)
$n$ is the term (in our case it is 10 since we want to find 10th partial sum -- sum until first 10 terms)
$d$ is the common difference (difference in term and the previous term) (in our case it is 0.5)

Substituting these into the formula, we get the 10th partial sum to be:

$s_{10}=\frac{10}{2}(2(0)+(10-1)(0.5))\\s_{10}=5(0+(9)(0.5))\\s_{10}=5(0+4.5)\\s_{10}=5(4.5)\\s_{10}=22.5$

So the sum of the first 10 terms is 22.5. Third answer choice is right.

8 0

2 years ago

Read 2 more answers

PLEASE ANSWER FAST WILL DO BRAINLIESTThe coordinate grid shows points A through K. What point is a solution to the system of ine

Alja [10]

Answer: points B (4,7) and I (9,3)

If the inequalities are

y > −2x + 10 and y> (½)x -2

Step-by-step explanation: If I interpreted the inequalities correctly, the attached graph shows them. It is possible that you meant y > 1/(2x-2) for the second inequality. If so, we start over!

You can test the values for all the points, but it appears that (4,7) and (9,3) both work.

The other coordinates appear to be outside the solution -- the dark-shaded area.

I hope this is your Brainliest answer. It was a lot of work!

4 0

3 years ago

Lol i need help . i would really appreciate it . thank you .

natulia [17]

Answer:

y= 3/5x + 1

Step-by-step explanation:

Slope intercept form is modeled by the equation y=mx+b.

M = slope, while B = y-intercept.

The y-intercept in this scenario equals (0, 1) or just simply 1.

The slope equals 3/5. This can be found with rise/run or y/x.

8 0

2 years ago

N artist makes three types of ceramic statues (large, medium, and small) at a monthly cost of $760 for 210 statues. The manufact

Arlecino [84]

Answer:

20, 90 and 100

Step-by-step explanation:

Total number of statues = 210

Assuming that a large statue = x, medium statue = y and a small statue = z

Then, x + y + z = 210........i

Also, we're told that the monthly cost is $760, so

5x + 4y + 3z = 760.........ii

Cost of selling is $3640, so then

26x + 18y + 15z = 3640.........iii

Solving i and ii simultaneously, we have

5x + 5y + 5z = 1050

5x + 4y + 3z = 760

Subtracting, we have

y + 2z = 290.........iv

Again, solving ii and iii simultaneously, we have

130x + 104y + 78z = 19760

130x + 90y + 75z = 18200

On subtracting, we have

14y + 3z = 1560.........v

And finally, solving iv and v simultaneously, we also have

14y + 28z = 4060

14y + 3z = 1560

On subtracting,

25z = 2500

z = 2500 / 25

z = 100

Substituting for z = 100 in iv, we have

y + 2(100) = 290

y + 200 = 290

y = 290 - 200

y = 90

Substituting for y = 90, and z = 100 in i

x + 90 + 100 = 210

x + 190 = 210

x = 210 - 190

x = 20

Therefore, large statues has to be 20, medium statues has to be 90, and small statues has to be 100

7 0

2 years ago