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vampirchik [111]
3 years ago
6

Need help!!!

Mathematics
2 answers:
Assoli18 [71]3 years ago
7 0

Answer:

73 mph during the second hour!

Step-by-step explanation:

Hour 1=54 mph

Hour 2=? mph

Hour 3=82 mph

Total=209 mph

this means that 209=82+54+?

Simplify it and you will get 73

73 mph

kvasek [131]3 years ago
6 0

Answer: 73

Step-by-step explanation:

Setting Up An Equation

The question provides the distances the train traveled in the first 3 hours

T = total distance

A = distance during 1st hour

B = distance during 2nd hour

C = distance during 3rd hour

the total distance traveled is equal to the sum of the distances of the first three hours so our equation would be

T = A + B + C

Solving For B

Since the question asks for the distance during the second hour, we need to find B

It is already given that A = 54, C = 82, and T = 209, so plug in the values and solve for B

T = A + B + C

B = T - A - C

B = 209 - 54 - 82

B = 73

Final Answer

B = 73

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3 years ago
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At this point, the function does not exist. If you were to draw a graph of it, there wouldn't be a y-value corresponding to x=1/3.
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