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vampirchik [111]
3 years ago
6

Need help!!!

Mathematics
2 answers:
Assoli18 [71]3 years ago
7 0

Answer:

73 mph during the second hour!

Step-by-step explanation:

Hour 1=54 mph

Hour 2=? mph

Hour 3=82 mph

Total=209 mph

this means that 209=82+54+?

Simplify it and you will get 73

73 mph

kvasek [131]3 years ago
6 0

Answer: 73

Step-by-step explanation:

Setting Up An Equation

The question provides the distances the train traveled in the first 3 hours

T = total distance

A = distance during 1st hour

B = distance during 2nd hour

C = distance during 3rd hour

the total distance traveled is equal to the sum of the distances of the first three hours so our equation would be

T = A + B + C

Solving For B

Since the question asks for the distance during the second hour, we need to find B

It is already given that A = 54, C = 82, and T = 209, so plug in the values and solve for B

T = A + B + C

B = T - A - C

B = 209 - 54 - 82

B = 73

Final Answer

B = 73

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scoray [572]

Answer18:

The quadrilateral ABCD is not a parallelogram

Answer19:

The quadrilateral ABCD is a parallelogram

Step-by-step explanation:

For question 18:

Given that vertices of a quadrilateral are A(-4,-1), B(-4,6), C(2,6) and D(2,-4)

The slope of a line is given m=\frac{Y2-Y1}{X2-X1}

Now,

The slope of a line AB:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{6-(-1)}{(-4)-(-4)}

m=\frac{7}{0}

The slope is 90 degree

The slope of a line BC:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{6-6}{(-4)-(-1)}

m=\frac{0}{(-3)}

The slope is zero degree

The slope of a line CD:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{(-4)-6}{2-2}

m=\frac{-10}{0}

The slope is 90 degree

The slope of a line DA:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{(-1)-(-4)}{(-4)-(2)}

m=\frac{3}{-6}

m=\frac{-1}{2}

The slope of the only line AB and CD are the same.

Thus, The quadrilateral ABCD is not a parallelogram

For question 19:

Given that vertices of a quadrilateral are A(-2,3), B(3,2), C(2,-1) and D(-3,0)

The slope of a line is given m=\frac{Y2-Y1}{X2-X1}

Now,

The slope of a line AB:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{2-3}{3-(-2)}

m=\frac{-1}{5}

The slope of a line BC:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{(-1)-2}{2-3}

m=\frac{-3}{-1}

m=3

The slope of a line CD:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{0-(-1)}{(-3)-2}

m=\frac{-1}{5}

The slope of a line DA:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{3-0}{(-2)-(-3)}

m=3

The slope of the line AB and CD are the same

The slope of the line BC and DA are the same

Thus, The quadrilateral ABCD is a parallelogram

3 0
3 years ago
What is -4 3/10 - 8 3/10
nadya68 [22]

Answer:

-12 3/5

Step-by-step explanation:

-4 3/10 - 8 3/10

The signs are the same so we add and then take the sign

4 3/10 + 8 3/10

Add the whole numbers

4+8 = 12

Add the fractions

3/10 + 3/10 = 6/10

Simplify the fraction

6/10 = 3/5

Put them together

12 3/5

Add the sign

-12 3/5

4 0
3 years ago
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A deep sea diver started at sea level (0 feet) and dove at a rate of 5.6 feet per minute. If the diver dove for ½ hour, what rat
Leona [35]

Given:

A deep sea diver started at sea level (0 feet).

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Time = \dfrac{1}{2} hour

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The rational number that represents his position relative to sea level.

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We know that,

1 hour = 60 minutes

\dfrac{1}{2} hour = 30 minutes

A deep sea diver, dove at a rate of 5.6 feet per minute.

Distance covered in 1 minute = 5.6 feet

Distance covered in 30 minute = 30 × 5.6 feet

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The diver dove 168 feet in \dfrac{1}{2} hour. Since it is below the sea level, therefore it should be negative.

So, the rational number that represents his position relative to sea level is -168 feet.

Therefore, the correct option is D.

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