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vampirchik [111]
3 years ago
6

Need help!!!

Mathematics
2 answers:
Assoli18 [71]3 years ago
7 0

Answer:

73 mph during the second hour!

Step-by-step explanation:

Hour 1=54 mph

Hour 2=? mph

Hour 3=82 mph

Total=209 mph

this means that 209=82+54+?

Simplify it and you will get 73

73 mph

kvasek [131]3 years ago
6 0

Answer: 73

Step-by-step explanation:

Setting Up An Equation

The question provides the distances the train traveled in the first 3 hours

T = total distance

A = distance during 1st hour

B = distance during 2nd hour

C = distance during 3rd hour

the total distance traveled is equal to the sum of the distances of the first three hours so our equation would be

T = A + B + C

Solving For B

Since the question asks for the distance during the second hour, we need to find B

It is already given that A = 54, C = 82, and T = 209, so plug in the values and solve for B

T = A + B + C

B = T - A - C

B = 209 - 54 - 82

B = 73

Final Answer

B = 73

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Answer:

C. {-5,-4, -3, 1, 2, 5}

Step by step explanation:

We have been given a graph and we are asked to find the domain of the relation represented in graph.

We can see that our graph is a series of unconnected points. Our function represents integer values. So we can see that our graph represents a discrete function.    

Since we know that domain of a discrete function is set of inputs values consisting of only certain values in an interval. .

The set of first value from each of the given points would made domain of our function. Upon looking at our graph we can see that domain of our function is -5,-4, -3, 1, 2 and 5.  

Therefore, option C is the correct choice.


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The table of values represents a function ​f(x).
NeX [460]

Answer:

The average rate of change over the interval [9,10] is greater than that over the interval [5,8] by 6490.

Step-by-step explanation:

The value of f(x) = 4052 for x = 9 and f(x) = 11014 for x = 10.

Therefore, the average rate of change of f(x) with respect to x over the interval [9,10] is given by  

= \frac{\textrm {Total change in value of f(x)}}{\textrm {Total change in value of x}}

= \frac{11014 - 4052}{10 - 9} = 6962

Now, the value of f(x) = 75 for x = 5 and f(x) = 1491 for x = 8.

Therefore, the average rate of change of f(x) with respect to x over the interval [5,8] is given by

= \frac{\textrm {Total change in value of f(x)}}{\textrm {Total change in value of x}}

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