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aliina [53]
3 years ago
15

What is a supplementary angle?

Mathematics
2 answers:
o-na [289]3 years ago
8 0

Supplementary angles are angles that usually share a common side, but they don't have to. If you joined them together, they would measure a straight angle and together they form a straight angle which measures 180°. If the sum of the measures of two angles is 180°, then the angles are classified as supplementary angles.

An example of a supplementary angle is provided in the image attached.

Lelu [443]3 years ago
5 0

Either of two angles whose sum is 180 degrees

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The numbers 1 through 15 are written on cards. One card is chosen at random. Event A is choosing a
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Step-by-step explanation:

the probability is always the number of desired cases over the number of all possible cases.

in our situation we have 15 cards.

that is the total possible cases when a random card is chosen.

how many desired cases do we have ?

a number NOT a multiple of 5.

how many are there ?

it is easier to say how many numbers there are being a multiple of 5 : 5, 10, 15

so, 3 numbers out of the 15 are multiple of 5.

that means

15 - 3 = 12 numbers of the 15 are NOT multiples of 5.

so, the probability to draw a card that is not a multiple of 5 is

12/15 = 4/5 = 0.8

the information about event B and even numbers is irrelevant for the question.

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2 years ago
△JKL has vertices at J(−2, 4), K(1, 6), and L(4, 4). Determine whether △JKL is a right triangle
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Answer:

Not a right triangle

Obtuse isosceles triangle.

Sides: J = 3.606   K = 6   L = 3.606

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3 years ago
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What is 15% of 60? Create a model to prove your answer (this is the question. I didn't really understand today's lesson in class
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A large tank is filled to capacity with 300 gallons of pure water. brine containing 5 pounds of salt per gallon is pumped into t
Licemer1 [7]
If A(t) is the amount of salt in the tank at time t, then the rate at which this amount changes over time is given by the ODE

A'(t)=\dfrac{3\text{ gal}}{1\text{ min}}\cdot\dfrac{5\text{ lb}}{1\text{ gal}}-\dfrac{3\text{ gal}}{1\text{ min}}\cdot\dfrac{A(t)\text{ lb}}{300+(3-3)t\text{ gal}}

A'(t)+\dfrac1{100}A(t)=15

We're told that the tank initially starts with no salt in the water, so A(0)=0.

Multiply both sides by an integrating factor, e^{t/100}:

e^{t/100}A'(t)+\dfrac1{100}e^{t/100}A(t)=15e^{t/100}
\left(e^{t/100}A(t)\right)'=15e^{t/100}
e^{t/100}A(t)=1500e^{t/100}+C
A(t)=1500+Ce^{-t/100}

Since A(0)=0, we have

0=1500+C\implies C=-1500

so that the amount of salt in the tank over time is given by

A(t)=1500(1-e^{-t/100})

After 10 minutes, the amount of salt in the tank is

A(10)=1500(1-e^{-1/10})\approx142.74\text{ lb}
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