Seven Hundred And Thirty Two
Answer:

Step-by-step explanation:
To solve this problem, simply set the binomial,
as greater than
, and solve for the value of y as you would solve an equation.
Thus:

Multiply both sides by 4



Subtract 3y from both sides


Add 4 to both sides


Divide both sides by 17


Therefore, the value of y that will make the binomial
greater than
is
.
The answer is the second one! n^2 +13