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dlinn [17]
3 years ago
9

Solve the problem –16 – 8 + 11 – 5 = ? A. –40 B. –18 C. 18 D. –2

Mathematics
1 answer:
ivolga24 [154]3 years ago
3 0

Simplify the expression and you get B. -18

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Lesechka [4]
Infinite solution for m
6 0
3 years ago
Triangle ABC has vertices A(- 3, - 4), B(16, - 2) and C(13, - 10) . Show algebraically that ABC is a right angled triangle.​
8_murik_8 [283]

Given:

The vertices of a triangle ABC are A(-3,-4), B(16,-2) and C(13,-10).

To show:

That the triangle ABC is a right angled triangle.​

Solution:

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The vertices of a triangle ABC are A(-3,-4), B(16,-2) and C(13,-10).

Using the distance formula, we get

AB=\sqrt{(16-(-3))^2+(-2-(-4))^2}

AB=\sqrt{(19)^2+(2)^2}

AB=\sqrt{361+4}

AB=\sqrt{365}

Similarly,

BC=\sqrt{\left(13-16\right)^2+\left(-10-\left(-2\right)\right)^2}

BC=\sqrt{73}

And,

AC=\sqrt{\left(13-\left(-3\right)\right)^2+\left(-10-\left(-4\right)\right)^2}

AC=\sqrt{292}

Now, add the square of two smaller sides.

BC^2+AC^2=(\sqrt{73})^2+(\sqrt{292})^2

BC^2+AC^2=73+292

BC^2+AC^2=365

BC^2+AC^2=(AB)^2

Since the sum of the square of two smaller sides is equal to the square of the largest side, therefore the given triangle is a right angle triangle by using Pythagoras theorem.

Hence proved.

7 0
3 years ago
How Do I do this equation
Mariulka [41]

Answer:

Part A 12 ≤ 6x ≤ 36

Part B 2 ≤ x ≤ 6

Step-by-step explanation:

5 0
3 years ago
A sinusoidal function whose frequency is 1/6pi
Lyrx [107]

Answer:

B. f(x)=9\sin (\frac{x}{3})+3

Step-by-step explanation:

We are given that,

The frequency of the function is \frac{1}{6\pi}

The maximum and minimum value is 12 and -6.

Also, the y-intercept is 3.

From the options, we have,

Options C and D have minimum value 6. So, they does not represent the given function.

We know, 'If a function has a period P, then the function a+f(bx+c) will have the period \frac{P}{|b|}.

Also, 'The frequency is the reciprocal of the period'.

So, function a+f(bx+c) will have the frequency \frac{|b|}{P}.

From the options, we see,

Option B have the frequency, \frac{\frac{1}{3}}{2\pi} i.e. \frac{1}{6\pi}.

Option A have the frequency, \frac{6\pi}{2\pi} i.e. 3

Thus, option A is not correct.

Hence, option B is the required sinusoidal function.

8 0
4 years ago
Read 2 more answers
Are two triangles ABC and A’B’C’ congruent ich hc = h‘c and sc = s‘c and alpha= alpha
vredina [299]

Step-by-step explanation:

are two triangles ABC and A’B’C’ congruent ich hc = h‘c and sc = s‘c and alpha= alpha

4 0
3 years ago
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