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katen-ka-za [31]
3 years ago
10

Are two triangles ABC and A’B’C’ congruent ich hc = h‘c and sc = s‘c and alpha= alpha

Mathematics
1 answer:
vredina [299]3 years ago
4 0

Step-by-step explanation:

are two triangles ABC and A’B’C’ congruent ich hc = h‘c and sc = s‘c and alpha= alpha

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What is the rise of y = 4/1 x -1
Setler [38]

Answer:

4

Step-by-step explanation:

3 0
3 years ago
Ellen and Michelle scored 48% of their teams points. If their team has a total of 50 points, how many points did they score ? ex
dexar [7]

Answer:

The answer is 24 points.


Step-by-step explanation:

A way to find out what the answer is is to use your calculator. Turn your percentage into a decimal.

So, let's put it this way.

50 x 0.48 = 24!




3 0
3 years ago
Read 2 more answers
Using the tree diagram below, what is the probability of getting tails and an even number?
N76 [4]

Answer:

1/4

Step-by-step explanation:

Chances of getting tails out of all the numbers (including heads)

Totals numbers (including heads & tails): 12

Tails & Even Number: 3

3/12 simplified to 1/4

5 0
1 year ago
3. Write an equation of a line that is perpendicular to the line x – 2y = 8.
xenn [34]

Answer:

y=0.5x+40

Step-by-step explanation:

Copy the  equation.

x-2y=8

Subtract x from both sides.

-2y=-x-8

Divide both sides by -2.

y=0.5x+4

Now we know the slope is 0.5.

Any line with a slope of 0.5 will be perpendiculr to the original line.

One that you can use is y=0.5x+40.

7 0
3 years ago
Geometry Select the correct answer from each drop-down menu. Given that , ° and °.
Alexxx [7]

\measuredangle BAC = 29°

Answer:

\measuredangle BOC =58°

Step-by-step explanation:

\measuredangle BDC = 29°...(Given) \\\because \measuredangle BAC = \measuredangle BDC\\(\angle 's \: subtended \: by\: same\: arc) \\\huge \purple {\boxed {\therefore \measuredangle BAC = 29°}} \\\\

Since, angle subtended on the center of the circle is twice the angle subtended on the circumference of the circle.

\therefore \measuredangle BOC =2\times \measuredangle BDC\\\therefore \measuredangle BOC =2\times 29°\\\huge \red {\boxed {\therefore \measuredangle BOC =58°}} \\

8 0
3 years ago
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