Using the normal distribution, it is found that the correct option is:
In a <em>normal distribution</em> with mean
and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
In this problem:
- The mean on the Wechsler Scale is of 100, hence
.
- The standard deviation is of 17, hence
.
- Brianna had an score of 117, hence

Then:



Hence, the option d is correct.
To learn more about the normal distribution, you can check brainly.com/question/24663213
so to find the slope we do y2- y1/ x2-x1
plug in the coordinates: (-6,4) (0,3)
3-4/ 0--6
3-4/0+6
= -1/6
Then using the formula of slop intercept form: y=mx+b........ use one of the coordinates to plug in
4= -1/6x+b...... multiply -6/1 on both sides of equation ( you do this so -1/6 and -6/1 can cancel out)
-24=b........ Use b to plug in y=mx+b---------> y= -1/6x-24
Answer:
a. square root is y = 
b. linear is y = x
c. cubic is 
d. quadratic is 
e. reciprocal squared is 
f. absolute value is y = |x|
g. reciprocal is 
h. cube root is ![y = \sqrt[3]{x}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%5B3%5D%7Bx%7D)
Step-by-step explanation:
Answer:
Kevin must add 1.2 gallons of 100% lemon juice to make a mixture of 50% lemon and 50% lime.
Step-by-step explanation:
Given : Kevin wants to make a mixture that is 50% lemon juice and 50% lime juice. 100% lesson juice should he add to a juice mixture that is 40% lemon juice and 60% lime juice to make 6 gallons of the 50% lemon 50% lime juice mixture.
To find : How much 100% lesson juice should he add to a juice mixture.
Solution :
According to question, we wants to make mixture where lemon = lime
We have to make 6 gallons, where
40% lemon juice require to make 6 gallon
i.e, 
and 60% lime juice require to make 6 gallon
i.e, 
Now, to make them equal subtract both of them

Therefore, he must add 1.2 gallons of 100% lemon juice to make a mixture of 50% lemon and 50% lime.
Hi fren,
x=<span><span>−y</span>+<span>1
and for the second one...
</span></span>y=<span><span>2x</span>+<span>2
</span></span>x-intercept >> <span>(<span><span>−1</span>,0</span>)
</span>y-intercept >> <span>(<span>0,2)</span></span><span>
</span>