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kondaur [170]
3 years ago
7

Please help

Mathematics
2 answers:
alexandr402 [8]3 years ago
3 0
\bf 3\sqrt[3]{2a} -6\sqrt[3]{2a}\qquad \stackrel{add ing~like-terms}{\implies }\qquad -3\sqrt[3]{2a}
Grace [21]3 years ago
3 0

Answer:

-3\sqrt[3]{2a}

Step-by-step explanation:

We have been given a  radical expression 3\sqrt[3]{2a} -6\sqrt[3]{2a} and we are asked to write our given expression in simplest form.

Using exponent property \sqrt[n]{x}=x^{\frac{1}{n} we can write our given expression as:

3*(2a)^{\frac{1}{3}}-6*(2a)^{\frac{1}{3}}

Since we can add or subtract variables with same powers and we have like bases and like exponents for our given expression, so we can subtract 6*(2a)^{\frac{1}{3}} from 3*(2a)^{\frac{1}{3}}

-3(2a)^{\frac{1}{3}}

Using exponent property x^{\frac{1}{n}=\sqrt[n]{x} we will get,

-3\sqrt[3]{2a}

Therefore, our given radical expression simplifies to -3\sqrt[3]{2a}.

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