Answer:
a)
a1 = log(1) = 0 (2⁰ = 1)
a2 = log(2) = 1 (2¹ = 2)
a3 = log(3) = ln(3)/ln(2) = 1.098/0.693 = 1.5849
a4 = log(4) = 2 (2² = 4)
a5 = log(5) = ln(5)/ln(2) = 1.610/0.693 = 2.322
a6 = log(6) = log(3*2) = log(3)+log(2) = 1.5849+1 = 2.5849 (here I use the property log(a*b) = log(a)+log(b)
a7 = log(7) = ln(7)/ln(2) = 1.9459/0.6932 = 2.807
a8 = log(8) = 3 (2³ = 8)
a9 = log(9) = log(3²) = 2*log(3) = 2*1.5849 = 3.1699 (I use the property log(a^k) = k*log(a) )
a10 = log(10) = log(2*5) = log(2)+log(5) = 1+ 2.322= 3.322
b) I can take the results of log n we previously computed above to calculate 2^log(n), however the idea of this exercise is to learn about the definition of log_2:
log(x) is the number L such that 2^L = x. Therefore 2^log(n) = n if we take the log in base 2. This means that
a1 = 1
a2 = 2
a3 = 3
a4 = 4
a5 = 5
a6 = 6
a7 = 7
a8 = 8
a9 = 9
a10 = 10
I hope this works for you!!
Answer:
anything above 1
Step-by-step explanation:
-3/2 = -1.5.
3 x -2 = -6
Nope
3 x -1 = -3
Nope
3 x 1 = 3 Yes!!
Answer:
(√3 tan x + 1) / (√3 - tan x)
Step-by-step explanation:
Answer:
okay just call my personal phone number it is (911) i hope that it make u feel better
Answer:
Therefore the company have to print either 47 or 12 t-shirt for its production cost to be $40 or less.
Step-by-step explanation:
Given that,
The function that models the production cost is
To find the number of t-shirt, we put f(t)=40 in given function.
∴40= 0.1t²-6t+100
⇒ 0.1t²-6t+100-40=0
⇒0.1 t²- 6t +60=0
⇒t²-60t+600=0
Applying quadratic formula 
, a=1, b= - 60 and c=600
= 47.32,12.67
≈47, 12
Therefore the company have to print either 47 or 12 t-shirt for its production cost to be $40 or less.
