Answer:
The 95% confidence interval for the true mean cholesterol content, μ, of all such eggs is between 226.01 and 233.99 milligrams.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find M as such

In which
is the standard deviation of the population and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 230 - 3.99 = 226.01
The upper end of the interval is the sample mean added to M. So it is 230 + 3.99 = 233.99.
The 95% confidence interval for the true mean cholesterol content, μ, of all such eggs is between 226.01 and 233.99 milligrams.
Answer:
(12,0), (3, -1) (0,-4/3)
Step-by-step explanation:
To do this problem, you have to plug in the x and y values. For example, the first one would be 12-9(0)=12, and so on.
Answer:
Increase Y by 2 and increase X by 3
Step-by-step explanation:
Answer:
No
Step-by-step explanation:
The rate of change is not the same
Answer:
The answer is B hope this helps