I guess that's f(x) = -3x^2+2
Well :
-3x^2+2=0
-3x^2=-2 / : (-3)
x^2= -2/-3
x^2= 2/3 / sqrt
x= +/ - sqrt(2)/sqrt(3)
We got the zero points.
x ~ +/- 0.81
f(0)= -3(0)^2 + 2
f(0)= 2
Mark three points:
(0.81;0)
(-0.81;0)
(0;2)
Connect with parabolic line and ya got a your graph
Answer:
L8
Step-by-step explanation:
We turn that upside-down
86 '? '88 '89 '90 '9I
Then obviously we can tell that ? is to be replaced by 87
86 '87 '88 '89 '90 '9I
Then we turn it back right-side up again, and we have:
I6, 06, 68, 88, L8, 98
Answer: L8
Hope this helps ;)
Well how many students are there in the class??<span />
Answer:
the equation of the line is y=1/2x-1
so all you have to do is graph that equation
Step-by-step explanation:
Pythagorean thoerem
we imagine the wall as a leg of a right triangle, the ladder is the hypotonuse and the distance from the bottom of the ladder to the wall is the other leg
so if we have a right triangle with leg length a and b and hypotnuse length c then
a²+b²=c²
so
given that one of the legs is 9ft (9 ft is the height of the triangle)
and the hypotnuse is 12 ft (length of ladder)
then say the last leg is x
so
x²+9²=12²
x²+81=144
mius 81 both sides
x²=63
sqrt both sides
x=√63
x=3√7
you should place it 3√7ft or about 7.9 or 8ft away
