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Yuki888 [10]
2 years ago
5

Find the indicated limit, if it exists. limit of f of x as x approaches 0 where f of x equals 7 minus x squared when x is less t

han 0, 7 when x equals 0, and 10 x plus 7 when x is greater than 0
Mathematics
1 answer:
hram777 [196]2 years ago
8 0

Answer:

answer is 7

Step-by-step explanation:

We are given a piecewise function which has a split at x=0

f(x) = f(x) = 7-x^2, x0

To find the limit, we have to find here left hand limit and right hand limit separately.

Here left hand limit for x tending to 0 is

limit of 7-x^2 as x tends to 0

= 7-0 = 7

Right limit = limit of 10x+7 as x tends to 0

=10(0)+7 = 7

Since right hand limit = left hand limit we have

there exists a limit for x=0 and the limit is 7

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PLEASE HELP ME as soon as possible!!
Alenkasestr [34]

Answer:

1/3 is answer.

I hope you got it. I had added solved answer too.

plz mark brainliest

8 0
3 years ago
Find the value of x.<br>A.5<br>B. 40<br>C. 45 <br>D. 20​
Alinara [238K]

(B) x = 40

Step-by-step explanation:

4x + 20 = 180

4x = 160

x = 40

3 0
2 years ago
Read 2 more answers
Cant figure this out
Snezhnost [94]

Answer: y^2 / p^3

Step-by-step explanation:

3 0
2 years ago
NEED HELP ASAP
mario62 [17]
1) (-7)3

2) PEMDAS; simplify (5-3)

3) 5^3, 5x5x5 and 125

4) -8^4

5) 36

6) 7

7) -100

8) 30

There ya go! Pretty sure they're all right!



5 0
3 years ago
Read 2 more answers
The given line passes through the points and (-4, -3) and (4, 1).
Debora [2.8K]

Answer:

The equation of the line is y - 3 = -2(x + 4)

Step-by-step explanation:

* Lets explain how to solve the problem

- The slope of the line which passes through the points (x1 , y1) and

  (x2 , y2) is m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

- The product of the slopes of the perpendicular lines = -1

- That means if the slope of a line is m then the slope of the

  perpendicular line to this line is -1/m

- The point-slope of the equation is y - y_{1}=m(x - x_{1})

* lets solve the problem

∵ A given line passes through points (-4 , -3) and (4 , 1)

∴ x1 = -4 , x2 = 4 and y1 = -3 , y2 = 1

∴ The slope of the line m=\frac{1-(-3)}{4-(-4)}=\frac{1+3}{4+4}=\frac{4}{8}=\frac{1}{2}

- The slope of the line perpendicular to this line is -1/m

∵ m = 1/2

∴ The slope of the perpendicular line is -2

- Lets find the equation of the line whose slope is -2 and passes

 through point (-4 , 3)

∵ x1 = -4 , y1 = 3

∵ m = -2

∵ y - y1 = m(x - x1)

∴ y - 3 = -2(x - (-4))

∴ y - 3 = -2(x + 4)

* The equation of the line is y - 3 = -2(x + 4)

4 0
3 years ago
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