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jeyben [28]
4 years ago
10

Please helpppppppp! ❤️

Mathematics
1 answer:
gulaghasi [49]4 years ago
3 0

woah this is some crazy is

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Compare the theoretical probability to the experimental probability of landing on H.
cestrela7 [59]

The correct statement comparing the theoretical and experimental probabilities is given as follows:

\frac{1}{4} < \frac{7}{25}.

<h3>What is a probability?</h3>

A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.

The theoretical probability is taken before any experiment. Since the four sections are equal, the theoretical probability is:

T(H) = 1/4.

The experimental probability is taken considering previous experiments. Out of 100 tosses, 28 landed on H, hence:

E(H) = 28/100 = 7/25.

Hence the correct statement is:

\frac{1}{4} < \frac{7}{25}.

More can be learned about probabilities at brainly.com/question/14398287

#SPJ1

4 0
2 years ago
Write an equation in standard form of the line that contains the point (-1,2) amd is perpendicular to y = 3x - 1
Strike441 [17]
Since it is perpendicular to y=3x-1, the slope must be a negative reciprocal.
there the slope of the perpendicular line is -\frac{1}{3} x

So now we have, 
y=- \frac{1}{3} x+b

To find b, we use the point that the line passes through and substitute it to the y and x values.

2=- \frac{1}{3} (-1)+b

which would give us b=5/3

Therefore, the equation of the line is 
y=- \frac{1}{3} x+ \frac{5}{3}
7 0
3 years ago
HELP ME !?!!!!?!?? Please
vovikov84 [41]

Answer:

Step-by-step explanation:i havent done something like this in a long time

7 0
3 years ago
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I am struggling could someone please help me.
ryzh [129]

Answer:

- 30 cud be the answer for the question, I'm not really sure

6 0
3 years ago
2.1 &amp; 2.2 Assessment: Vertex &amp; Standard Form of Quadratic Functions
Brums [2.3K]

~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill

\begin{cases} h=1\\ k=-9 \end{cases}\implies y=a(x-1)^2 - 9\qquad \textit{we also know that} \begin{cases} x=2\\ y=-7 \end{cases} \\\\\\ -7=a(2-1)^2-9\implies 2=a(1)^2\implies 2=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill {\Large \begin{array}{llll} y=2(x-1)^2 -9 \end{array}} ~\hfill

6 0
1 year ago
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