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Margaret [11]
2 years ago
9

Evaluate the function.

Mathematics
2 answers:
Lunna [17]2 years ago
7 0
20
...........................
Sav [38]2 years ago
6 0
The correct answer is 20
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What is the answer to this----->7/8-5/6
dlinn [17]
<span>7/8-5/6
Multiply until both fractions have the same common denominator.
21/24 - 20/24
Subtract the numerators but NOT the denominators.
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3 0
3 years ago
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Answer the question with explanation;​
PSYCHO15rus [73]

Answer:

The statement in the question is wrong. The series actually diverges.

Step-by-step explanation:

We compute

\lim_{n\to\infty}\frac{n^2}{(n+1)^2}=\lim_{n\to\infty}\left(\frac{n^2}{n^2+2n+1}\cdot\frac{1/n^2}{1/n^2}\right)=\lim_{n\to\infty}\frac1{1+2/n+1/n^2}=\frac1{1+0+0}=1\ne0

Therefore, by the series divergence test, the series \sum_{n=1}^\infty\frac{n^2}{(n+1)^2} diverges.

EDIT: To VectorFundament120, if (x_n)_{n\in\mathbb N} is a sequence, both \lim x_n and \lim_{n\to\infty}x_n are common notation for its limit. The former is not wrong but I have switched to the latter if that helps.

7 0
2 years ago
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Can anyone help me with my math homework plz
Svetach [21]

Answer:

1. 136

2. 55

3. 53

4. 110

5. 61

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3 years ago
If a simple harmonic motion is described by x = 3 cos(πt), starting from t = 0 s, what is the first occurrence of a value of t f
poizon [28]

Answer:

The first occurence of t for which x = 0 is t = 0.5.

Step-by-step explanation:

The harmonic motion is described by the following equation.

x(t) = 3\cos{\pi t}

What is the first occurrence of a value of t for which x = 0?

This is t when x(t) = 0. So

x(t) = 3\cos{\pi t}

3\cos{\pi t} = 0

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\cos{\pi t} = 0

The inverse of the cosine is the arcosine. So we apply the arcosine function to both sides of the equality.

\arccos{\cos{\pi t}} = \arccos{0}

\pi t = \frac{\pi}{2}

t = \frac{\pi}{2 \pi}

t = \frac{1}{2}

t = 0.5

The first occurence of t for which x = 0 is t = 0.5.

3 0
2 years ago
Which net represents this triangular prism?
Anarel [89]

Answer:

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