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krek1111 [17]
2 years ago
9

There are how many chromosomes in a human zygote? Question 4 options: 42 46 48 64.

Mathematics
1 answer:
AlladinOne [14]2 years ago
7 0

Answer:

46

Step-by-step explanation:

23 chromosomes from the ovum, 23 chromosomes from the sperm.

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What is the converse of the conditional statement?
dem82 [27]

Answer:

according to me 1st option seems to be correct❤️

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3 years ago
Are these triangles congruent? If so, name the triangle congruence method.
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Answer:

The answer you chose is correct

Step-by-step explanation:

4 0
3 years ago
Lagrange multipliers have a definite meaning in load balancing for electric network problems. Consider the generators that can o
Ivahew [28]

Answer:

The load balance (x_1,x_2,x_3)=(545.5,272.7,181.8) Mw minimizes the total cost

Step-by-step explanation:

<u>Optimizing With Lagrange Multipliers</u>

When a multivariable function f is to be maximized or minimized, the Lagrange multipliers method is a pretty common and easy tool to apply when the restrictions are in the form of equalities.

Consider three generators that can output xi megawatts, with i ranging from 1 to 3. The set of unknown variables is x1, x2, x3.

The cost of each generator is given by the formula

\displaystyle C_i=3x_i+\frac{i}{40}x_i^2

It means the cost for each generator is expanded as

\displaystyle C_1=3x_1+\frac{1}{40}x_1^2

\displaystyle C_2=3x_2+\frac{2}{40}x_2^2

\displaystyle C_3=3x_3+\frac{3}{40}x_3^2

The total cost of production is

\displaystyle C(x_1,x_2,x_3)=3x_1+\frac{1}{40}x_1^2+3x_2+\frac{2}{40}x_2^2+3x_3+\frac{3}{40}x_3^2

Simplifying and rearranging, we have the objective function to minimize:

\displaystyle C(x_1,x_2,x_3)=3(x_1+x_2+x_3)+\frac{1}{40}(x_1^2+2x_2^2+3x_3^2)

The restriction can be modeled as a function g(x)=0:

g: x_1+x_2+x_3=1000

Or

g(x_1,x_2,x_3)= x_1+x_2+x_3-1000

We now construct the auxiliary function

f(x_1,x_2,x_3)=C(x_1,x_2,x_3)-\lambda g(x_1,x_2,x_3)

\displaystyle f(x_1,x_2,x_3)=3(x_1+x_2+x_3)+\frac{1}{40}(x_1^2+2x_2^2+3x_3^2)-\lambda (x_1+x_2+x_3-1000)

We find all the partial derivatives of f and equate them to 0

\displaystyle f_{x1}=3+\frac{2}{40}x_1-\lambda=0

\displaystyle f_{x2}=3+\frac{4}{40}x_2-\lambda=0

\displaystyle f_{x3}=3+\frac{6}{40}x_3-\lambda=0

f_\lambda=x_1+x_2+x_3-1000=0

Solving for \lambda in the three first equations, we have

\displaystyle \lambda=3+\frac{2}{40}x_1

\displaystyle \lambda=3+\frac{4}{40}x_2

\displaystyle \lambda=3+\frac{6}{40}x_3

Equating them, we find:

x_1=3x_3

\displaystyle x_2=\frac{3}{2}x_3

Replacing into the restriction (or the fourth derivative)

x_1+x_2+x_3-1000=0

\displaystyle 3x_3+\frac{3}{2}x_3+x_3-1000=0

\displaystyle \frac{11}{2}x_3=1000

x_3=181.8\ MW

And also

x_1=545.5\ MW

x_2=272.7\ MW

The load balance (x_1,x_2,x_3)=(545.5,272.7,181.8) Mw minimizes the total cost

5 0
3 years ago
Which parent function is graphed below
aleksandrvk [35]

Answer:

the answer for this question is c because that is the answer

4 0
3 years ago
3 + 11 . (8 - 4) ÷ (5 + 6) - 4
Irina-Kira [14]

Answer:

3

Step-by-step explanation:

3 + 11 ⋅ ( 8 − 4 ) ÷ ( 5 + 6 ) − 4

 Subtract  4  from  8 .

3 + 11 ⋅ 4 ÷ ( 5 + 6 ) − 4

Multiply  11  by  4 .

3 + 44 ÷ ( 5 + 6 ) − 4

Find the common denominator.  

Add  5  and  6 .

3 + 44 ÷ 11 − 4

Write  3  as a fraction with denominator  1 .

3/ 1 + 44 ÷ 11 − 4

Multiply  3/ 1  by  11/ 11 .

3/ 1 ⋅ 11 /11 + 44 ÷ 11 − 4

Multiply  3/ 1  and  11 /11 .

3 ⋅ 11 /11 + 44 ÷ 11 − 4

Write  − 4  as a fraction with denominator  1 .

3 ⋅ 11 /11 + 44 ÷ 11 +  − 4 /1

Multiply  − 4 /1  by  11 /11 .

3 ⋅ 11 /11 + 44 ÷ 11 + − 4 /1  ⋅ 11 /11

Multiply  

− 4 /1  and  11 /11 .

3 ⋅ 11 /11 + 44 ÷ 11 +   − 4 ⋅ 11 /11

Combine the numerators over the common denominator.

3 ⋅ 11 + 44 − 4 ⋅ 11 /11

Simplify each term.  

Multiply  3  by  11 .

33 + 44 − 44 ⋅ 11/ 11

Multiply  − 4  by  11 .

33 + 44 − 44 /11

Simplify the expression.  

Add  33  and  44 .

77 − 44/ 11

Subtract  44  from  77 .

33 /11

Divide  33 by  11 .

3

5 0
3 years ago
Read 2 more answers
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