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3 years ago

If William made 620 babysitting. And next year he made 340%more how much money will he have

Mathematics

1 answer:

chubhunter [2.5K]3 years ago

4 0

Answer:

$2180

hope this helps :)

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There are 303 Students. There are 147 Girls. How Many Boys Are there?

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There are 156 boys at the school

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3 years ago

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The large clock below hangs in Isaac's living room. If the radius of this clock is 3.5 feet, what is its circumference? Round yo

Degger [83]

Answer:

22.0

Step-by-step explanation:

knowing the radius is 3.5 -

and the formula for the circumfrence -

2 pi r

we can then use the radius -

2 * 3.14 * 3.5

which is 21.98 -

rounding to 22.0

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3 years ago

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B с A Find the length of “c” using the Pythagorean Theorem.

cupoosta [38]

5.8
a2+b2=c and the once you have c which was
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3 years ago

Based on corresponding angles and vertical angles, which angles must always be congruent to the angles glven?

Gre4nikov [31]

Answer:

When two lines intersect they form two pairs of opposite angles, A + C and B + D. Another word for opposite angles are vertical angles. Vertical angles are always congruent, which means that they are equal. Adjacent angles are angles that come out of the same vertex

8 0

3 years ago

A small lawnmower company produced 1,500 lawnmowers in 2008. In an effort to determine how maintenance-free these units were, th

ikadub [295]

Answer:

The 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

Step-by-step explanation:

The (1 - α)% confidence interval for the average using the finite correction factor is:

$CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}$

The information provided is:

$N=1500\\n=183\\\sigma=1.47\\\bar x=3.3$

The critical value of z for 95% confidence level is,

z = 1.96

Compute the 95% confidence interval for the average number of years until the first major repair as follows:

$CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}$

$=3.3\pm 1.96\times\frac{1.47}{\sqrt{183}}\times\sqrt{\frac{1500-183}{1500-1}}\\\\=3.3\pm 0.19964\\\\=(3.10036, 3.49964)\\\\\approx (3.1, 3.5)$

Thus, the 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

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3 years ago