Answer:
C. The distribution for town A is symmetric, but the distribution for
town B is negatively skewed.
Step-by-step Explanation:
From the box plots attached in the diagram below, which shows data of low temperatures for town A and town B for some days, we can compare the shapes of the box plot by visually analysing both box plots and how the data for each town is distributed.
=> For town A, the shape of the box plot is symmetric because both quartiles seem equal, and the median also divides the rectangular box into two equal halves. Both whiskers also appear to be of equal lengths.
The box plot for Town A takes a symmetric shape, and this shows a typical normal distribution of data.
=> On the other hand, Town B data distribution is different. The median seem close to the top half of the box and does not divide the box into equal halves. This shows the distribution is skewed. Since the whisker is shorter from the upper end of the box to the left side, we can infer that the distribution for Town B is skewed to the left, and it is negatively skewed.
=> The right comparison of the shapes of the box plots is "C. The distribution for town A is symmetric, but the distribution for town B is negatively skewed."
Answer:
La mediana de un conjunto de números es el número del medio del conjunto (después de que los números se hayan ordenado de menor a mayor).
Step-by-step explanation:
Digamos que tienes estos números, 4, 7, 2, 9, 7, 6 y 4. primero, los pones en orden de menor a mayor (2, 4, 4, 6, 7, 7, 9), y luego usted determina qué número está en el medio, que es 6.
Answer:
x = 7
Step-by-step explanation:
if ABC ~ DEF than AB ~ ED, AC ~ DF, and CB ~ FE
The ratio of AB to ED is given as 5/30 = 1/6
For AC ~ ED the ratio would be same x/42 = 1/6 cross multiply it
6x = 42
x = 7
I can't answer cause u didn't show the angles
Answer:
BC:BN=8:3
Step-by-step explanation:
ABCD is a trapezoid and there is a point m which belongs to AD such that AM:MD=3:5.Line "l" parallel to AB intersects the diagonal AC at p and BD at N.
Now, we know that the parallel lines divide the transversal into the segments with equal ratio, therefore, BN:NC=AM:MD
But, BC= BN+NC
Therefore, BC:BN=(BN+NC):BN
⇒BC:BN=(3+5):3
⇒BC:BN=8:3