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yKpoI14uk [10]
3 years ago
7

The length of a cell phone is 1.41.4 inches and the width is 4.44.4 inches. The company making the cell phone wants to make a ne

w version whose length will be 1.751.75 inches. Assuming the side lengths in the new phone are proportional to the old phone, what will be the width of the new phone?
Mathematics
1 answer:
4vir4ik [10]3 years ago
7 0

Answer:

vhasbwwsbawajassbjbsjqsbajbjaqbasqqsjbbsbjsbjabjsqbsbjbjsqbjsqbjsqbjsbsjqbjsqbjsjbsqbjsabsqjaqsa

Step-by-step explanation:

swhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhqkjshkqjswhbwjqnakksjqkjhqkjhskjqhskjshqkjshqkshkshqkjshqkjshqkjshqksjhqkjhqksjhq

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How do you get why by itself in this equation? 4x+5y=5
Alja [10]

Answer:

first we get y on one side by itself.

4x+5y=5

we'll move x to the other side.

4x-4x+5y=5-4x

simplify.

5y=5-4x

now we get rid of the coefficient on y.

5y/5=(5-4x)/5

simplify.

y=5/5-4x/5

y=1- \frac{4}{5}x

The answer is y=1-\frac{4}{5}x

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Help please !!!!!!! Thanks in advance
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Does someone mind helping me with this problem? Thank you!
faltersainse [42]

\frac{10-(3 \cdot 2^2 - 23)}{(1 + 10^2)-2^2 \cdot 5^2} =

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\left(1+10^2\right)-2^2\cdot \:5^2 =  101-2^2\cdot \:5^2 = 101-4\cdot \:5^2 =101-4\cdot \:25 =101-100 = 1

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