The length of a cell phone is 1.41.4 inches and the width is 4.44.4 inches. The company making the cell phone wants to make a ne w version whose length will be 1.751.75 inches. Assuming the side lengths in the new phone are proportional to the old phone, what will be the width of the new phone?
1 answer:
Answer:
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Step-by-step explanation:
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Answer:
10.6
Step-by-step explanation:
53/5
Answer:
42 because 3 tens is 30 and 12 ones is 12. so you do 30 + 12 = 42
Step-by-step explanation:
Pathagory and Theorem
a^2+b^2=c^2
(x-3)^2+(x-4)^2=6^2
expand:
2x^2-14x+25=36
2x^2-14x-11=0
x=(\sqrt{71}+7)/2
perimeter=(x-3)+(x-4)+6=2x-1
insert the value for x into 2x-1
Hope that helps :)
3w-7w-12=2w-6
