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liraira [26]
2 years ago
12

Multiply. 5x^2-6x+2 4x^2-3x

Mathematics
1 answer:
EastWind [94]2 years ago
3 0
20x^4-39x^3+26x^2-6x
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Use the scale drawing and the scale factor to enlarge a square that has a side length of 12 in. Scale factor= 3 in:2m.
podryga [215]

Given:

The side of square = 12 in.

Scale factor of enlargement = 3 in : 2 m

To find:

The proportion that is use to solve the side length, x, of the enlarged square.

Solution:

Let, the side of length of enlarged square = x m

In case of enlargement the corresponding sides are proportional.

\dfrac{3}{12}=\dfrac{2}{x}

3x=2\times 12

3x=24

Divide both sides by 3.

x=\dfrac{24}{3}

x=8

Therefore, the required proportion is \dfrac{3}{12}=\dfrac{2}{x} and the side length of the square after enlargement is 8 m.

4 0
3 years ago
Which set of data is correct for the quadratic relation f(x) = 5(x -
Burka [1]

Answer:

Direction parabola opens upward.

Vertex of parabola is (27,-9).

Axis of symmetry is x=27.

Step-by-step explanation:

Note: Option sets are not correct.  

The vertex form of a parabola is

y=a(x-h)^2+k    ...(1)

where, (h,k) is vertex and x=h is the axis of symmetry.

If a<0, then parabola opens downward and if a>0, then parabola opens upward.

The given function is

f(x)=5(x-27)^2-9     ...(2)

On comparing (1) and (2), we get

a=5>0, so direction parabola opens upward.

h=27,k=-9, so vertex of parabola is (27,-9).

So, axis of symmetry is x=27.

6 0
4 years ago
Suppose triangle ABC will be dilated using the rule . What will be the distance from the center of dilation, Q, to the image of
Blababa [14]

Answer:

4

Step-by-step explanation:

The rule of dilation is D_{Q,\frac{2}{3}}. This means that each distance QX' is equal to \dfrac{2}{3}QX, where X is initial point and X' is its image after dilation.

Since QA=6, then

QA'=\dfrac{2}{3}\cdot 6=4.

6 0
3 years ago
Read 2 more answers
ALL MY POINTS PLZ BE RIGHT
shepuryov [24]

Answer:

-xy^6 +2y -6

Step-by-step explanation:

(-6x^2 y^8+12xy^3-36xy^2)

-------------------------------------------

6xy^2

Divide each term by 6 in the numerator and denominator

(-6/6x^2 y^8+12/6xy^3-36/6xy^2)

-------------------------------------------

6/6xy^2

-x^2y^8 +2xy^3 -6xy^2

---------------------------------

xy^2

Divide each term by x in the numerator and denominator

-x^2/xy^8 +2x/xy^3 -6x/xy^2

---------------------------------

x/xy^2

-xy^8 +2y^3 -6y^2

---------------------------------

y^2

Divide each term by y^2 in the numerator and denominator

Remember when dividing, we subtract the exponents

-xy^8/y^2 +2y^3/y^2 -6y^2/y^2

---------------------------------

y^2 /y^2

-xy^6 +2y^1 -6

---------------------------------

1

-xy^6 +2y -6

7 0
3 years ago
Read 2 more answers
A reflection of (–4, 5) over the x-axis is located in
olganol [36]
It’s gonna be in quadrant III because the rule for x-axis is -> (x,-y).
8 0
3 years ago
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