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3 years ago

Fine the solution of 4x^2+4x+1=0

Mathematics

2 answers:

Natalka [10]3 years ago

7 0

Answer:

x = -1/2

Step-by-step explanation:

Lena [83]3 years ago

7 0

Answer:

x = - $\frac{1}{2}$ with multiplicity 2

Step-by-step explanation:

given 4x² + 4x + 1 = 0

This is a perfect square of the type

(a + b)² = a² + 2ab + b²

4x² = (2x)² ⇒ a = 2x, 1 = 1² ⇒ b = 1, and

2ab = 2 × 2x × 1 = 4x

4x² + 4x + 1 = 0

(2x + 1)² = 0, hence

x = - $\frac{1}{2}$ with multiplicity 2

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3 years ago

Read 2 more answers

Find the value of below algebriac expression for x=2,y=-1 and z=2 i. 4x2−3y2+5z24x2−3y2+5z2 ii. 3x3−2x(4yz+5x2)3x3−2x(4yz+5x2) i

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Answer:

i. 33

ii. 1488

iii. 65

Step-by-step explanation:

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Putting the values x=2, y=-1 and z=2

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Putting the values x=2, y=-1 and z=2

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[1536 - 48]

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iii. 1−4x(yz+3xy)

Putting the values x=2, y=-1 and z=2

[1 - 4 × 2((-1)×2 + 3×2×(-1))]

[1- 8(-2 + (-6))]

[1- 8 (-2 -6)]

[1 - 8(-8)]

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