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Valentin [98]
3 years ago
5

Solve by substitution. x plus yx+y equals=1010 yy equals=xplus+22 Select the correct choice below​ and, if​ necessary, fill in t

he answer box to complete your choice.
a. The solution of the system is nothing. ​(Type an ordered​ pair, using integers or​ fractions.)
b. The system has infinitely many solutions.
c. The system has no solution.
Mathematics
1 answer:
Phantasy [73]3 years ago
5 0
X + y = 10
y = x + 2

so sub in x + 2 for y back into the first equation

x + y = 10
x + x + 2 = 10
2x + 2 = 10
2x = 10 - 2
2x = 8
x = 8/2
x = 4

y = x + 2
y = 4 + 2
y = 6

solution is : (4,6)
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Rodger has 47 cars . Can he group the cars in more than two ways?
deff fn [24]
First of all, Rodger must be making some serious cash to have 47 cars. Going back to the question, he can not group the cars in more than 2 ways. He can only group it in 1 way, 47 groups of 1. Pls brainliest
4 0
3 years ago
I’m using this app so much but i really do appreciate the help pleasee no wrong answers
12345 [234]

Answer:

C is correct

Step-by-step explanation:

a is wrong because: 1*-1*-1*-1 =1

b) 1*1*1*1 =1

d) 1*-1*1*1 =1

only c 1*-1*-1*1 =-1 at the end of polynomial

6 0
3 years ago
How to do the fractions
Alenkasestr [34]

you could either multiply straight away or you could simplify right then so that you wouldn't have to it later.

20/5 * 5/2

your answer would be 10 either way

3 0
3 years ago
A total of 397 tickets were sold for the school play. They were either adult tickets or student tickets. There were 53 fewer stu
Arturiano [62]
We know:
397 total
53 fewer student tickets than adult tickets

Variables: A for adult tickets, S for student tickets

Known Equations:
a + s = 397
a = s + 53

Solving:
2s + 53 = 397 so 2s = 344 so s = 172

s + a = 397
172 + (172 + 53) = 397 so 172 + 225 = 397

Adult tickets sold: 225
Student tickets sold: 172


4 0
3 years ago
Use any method to solve the equation. If necessary, round to the nearest hundredth.
vlada-n [284]

Here, in order to find the solutions to the quadratic equation - x² + x - 30 = 0, we will use factorization method.

In the method, we will split 30, in such factors, which when added or subtracted gives us 1,  and when multiplied gives us -30.

So, we will use, -5 and 6. When they are added they will give us 1 and when multiplied they will give us -30 as answer.

Now, the equation will be written as -

x² - 5x + 6x - 30 = 0

Taking common, we get

x(x - 5) +6(x-5) = 0

(x-5)(x+6) = 0

So, x - 5 = 0 and x +6 = 0, we will get, x = 5 and x = - 6

<u>Thus, the correct option is C). x = 5 and -6</u>

4 0
4 years ago
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