The function, g(x), has a constant rate of change and will increase at a faster rate than the function f(x) for all the values of x.
Given:
g(x) = 5/2 x -3 ..... (1)
f(x) = - 3.5 at x = 0
So, putting the value of x=0 in equation (1) for comparison. We get,
g(x) at x = 0
=> g(x) = 5/2 x (0) - 3
=> g(x) = -3
In this value of x function g(x) is faster than function f(x) having a value equal to -3.5.
Similarly, put x = 1 in equation (1) for comparison. We get,
=> g(x) = 5/2 x (1) - 3
=> g(x) = (5-6)/2
=> g(x) = -1/2
In this value of x function g(x) is faster than function f(x) having a value equal to -1.
Similarly, put x = 2 in equation (1) for comparison. We get,
=> g(x) = 5/2 x (2) - 3
=> g(x) = (5-3)
=> g(x) = 2
In this value of x function g(x) is faster than function f(x) having a value equal to 1.5.
Similarly, put x = 3 in equation (1) for comparison. We get,
=> g(x) = 5/2 x (3) - 3
=> g(x) = (15/2 - 3)
=> g(x) = 7.5 - 3
=> g(x) = 4.5
In this value of x function g(x) is faster than function f(x) having a value equal to 4.
Therefore, for all values of x function g(x) is faster than function f(x).
function f(x).
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It would be equal to 1 7/8
Missing: 360 | Must include: 360
look at
https://www.google.com/search?q=x+%3D+4.+5x+%2B23x%5E3+-+360&rlz=1CAJAIV_enUS838&oq=x+%3D+4.+5x+%2B23x%5E3+-+360&aqs=chrome..69i57&sourceid=chrome&ie=UTF-8&safe=active&ssui=on
Answer:
0.332
Step-by-step explanation:
given series
1/4, 1/16,1/64.1/256
this is geometric series
where common ratio r is given by
nth term/ (n-1)th term
let the second term is nth term and first term is (n-1)th term
r = 1/16 / (1/4) = 1/4
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sum of series is given by
a (1-r^n)/1-r
where a is first term
n is the number of terms
r is the common ration
___________________________________________
in the given series
1/4, 1/16,1/64.1/256
a = 1/4
r = 1/4
n = 4
thus ,
sum = 1/4(1-(1/4)^4)/ (1-1/4)
sum = 1/4(1-(1/256)/(4-1)/4
sum = 1/4((256-1)/256 / 3/4
1/4 in numerator and denominator gets cancelled
sum =( 255/256*3) = 255/768 = 0.332
Thus, sum of series is 0.332.
