A cross-country train travels at a steady speed. It covers 15 miles in 20

Mathematics

1 answer:

skelet666 [1.2K]4 years ago

5 0

Answer:

i think its 225 but i can still be wrong

You might be interested in

Suppose triangle ABC will be dilated using the rule . What will be the distance from the center of dilation, Q, to the image of

Blababa [14]

Answer:

Step-by-step explanation:

The rule of dilation is $D_{Q,\frac{2}{3}}.$ This means that each distance QX' is equal to $\dfrac{2}{3}QX,$ where X is initial point and X' is its image after dilation.

Since QA=6, then

$QA'=\dfrac{2}{3}\cdot 6=4.$

6 0

3 years ago

Read 2 more answers

Find dy/dx in the following<br> 1) y=x^[10] +10^[x] +e^[x]<br> 2) y=㏒ x +e^[x]+√x - 1/x

kakasveta [241]

1. in picture 1

2. in picture 2

Hope this helps :T

Also I am not so shure about 2, but I am 98% shure 1 is right.

6 0

3 years ago

A computer chip has the dimensions 8mm x 8mm but the scale is drawn with the ...

Yuliya22 [10]

Given that the chip has a dimension of 8 mm by 8 mm which can be written as 0.8 cm by 0.8 cm, is drawn to scale and the dimensions of the plot is 4 cm by 4 cm, the scale of the drawing will be:
0.8 cm is represented by 4 cm
thus;
4 cm rep 0.8 cm
1 cm rep 0.2 cm
The answer is:
1 cm rep 0.2 cm

6 0

3 years ago

A players kinetic energy will be most affected by his

miskamm [114]

Velocity

Formula wise:
1/2 x mass x velocity^2

8 0

3 years ago

Read 2 more answers

How do you find a vector that is orthogonal to 5i + 12j ?

Rashid [163]

$\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad \cfrac{a}{b}\\\\
slope=\cfrac{a}{{{ b}}}\qquad negative\implies -\cfrac{a}{{{ b}}}\qquad reciprocal\implies - \cfrac{{{ b}}}{a}\\\\
-------------------------------\\\\$

$\bf \boxed{5i+12j}\implies 
\begin{array}{rllll}
\ \textless \ 5&,&12\ \textgreater \ \\
x&&y
\end{array}\quad slope=\cfrac{y}{x}\implies \cfrac{12}{5}
\\\\\\
slope=\cfrac{12}{{{ 5}}}\qquad negative\implies -\cfrac{12}{{{ 5}}}\qquad reciprocal\implies - \cfrac{{{ 5}}}{12}
\\\\\\
\ \textless \ 12, -5\ \textgreater \ \ or\ \ \textless \ -12,5\ \textgreater \ \implies \boxed{12i-5j\ or\ -12i+5j}$

if we were to place <5, 12> in standard position, so it'd be originating from 0,0, then the rise is 12 and the run is 5.

so any other vector that has a negative reciprocal slope to it, will then be perpendicular or "orthogonal" to it.

so... for example a parallel to <-12, 5> is say hmmm < -144, 60>, if you simplify that fraction, you'd end up with <-12, 5>, since all we did was multiply both coordinates by 12.

or using a unit vector for those above, then

$\bf \textit{unit vector}\qquad \cfrac{\ \textless \ a,b\ \textgreater \ }{||\ \textless \ a,b\ \textgreater \ ||}\implies \cfrac{\ \textless \ a,b\ \textgreater \ }{\sqrt{a^2+b^2}}\implies \cfrac{a}{\sqrt{a^2+b^2}},\cfrac{b}{\sqrt{a^2+b^2}}
\\\\\\
\cfrac{12,-5}{\sqrt{12^2+5^2}}\implies \cfrac{12,-5}{13}\implies \boxed{\cfrac{12}{13}\ ,\ \cfrac{-5}{13}}
\\\\\\
\cfrac{-12,5}{\sqrt{12^2+5^2}}\implies \cfrac{-12,5}{13}\implies \boxed{\cfrac{-12}{13}\ ,\ \cfrac{5}{13}}$

4 0

3 years ago