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Rus_ich [418]
2 years ago
9

Find dy/dx in the following 1) y=x^[10] +10^[x] +e^[x] 2) y=㏒ x +e^[x]+√x - 1/x

Mathematics
1 answer:
kakasveta [241]2 years ago
6 0

1. in picture 1

2. in picture 2

Hope this helps :T

Also I am not so shure about 2, but I am 98% shure 1 is right.

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Find the slope of the line that passes through (87, 91) and (88, -4).
Elanso [62]
<h2>Answer:    slope = - 95</h2><h2> </h2>

Step-by-step explanation:    

      The question gives us two points, (87, 91) and (88, -4), from which we can find the slope and later the equation of the line.

<u> </u>

<u>Finding the Slope</u>  

The slope of the line (m) = (y₂ - y₁) ÷ (x₂ - x₁)      

                                        =  (91 - (- 4)) ÷ (87 - 88)    

                                        =  - 95

<em><u /></em>

<em><u /></em>

<em><u>Checking my answer:</u></em>

<em>Finding the Equation</em>  

We can now use the point-slope form (y - y₁) = m(x - x₁)) to write the equation for this line:  

                                ⇒  y - (-4) =  - 95 (x - 88)

                                       y + 4 =  - 95 (x - 88)

<em>To test my answer, I have included a Desmos Graph that I graphed using the information provided in the question and my answer.</em>

5 0
2 years ago
A train traveled from Station A to Station B at an average speed of 80 kilometers per hour and then from Station B to Station C
earnstyle [38]

Answer:

(i). Average speed = 75 km per hour

(ii). Average speed = 75 km per hour

Step-by-step explanation:

This question is incomplete; here is the complete question.

A train traveled from station A to station B at an average speed of 80 kilometers per hour and then from station B to station C at an average of 60 kilometers per hour. If the train did not stop at station b, what was the average speed at which the train traveled from station A to C?

(i). The distance that the train traveled from station A to station B was 4 times the distance that train traveled from station B to station C.

(ii). The amount of time it took to the train to travel from station A to station B is 3 times the amount of time that it took the train to travel from station B to station C.

(i) Let the distance between station B and station C = x km

So the distance between Station A and station B = 4x km

Therefore, time to travel the distance x km with 80 km per hour = \frac{\text{Distance traveled}}{\text{Speed}}

= \frac{4x}{80}

Similarly time taken to travel between station B and station C with speed 60 km per hour = \frac{x}{60} km per hour

Now average speed between station A and station C = \frac{\text{Total distance between station A and station C}}{\text{time taken to travel}}

= \frac{4x+x}{\frac{4x}{80}+\frac{x}{60}}

= \frac{5x}{\frac{4x}{60} }

= \frac{5\times 60}{4}

= 75 km per hour

(ii). Let the train took the time to cover the distance between station B and station C = t hours

Therefore, time taken by the train between station A and B = 3t

Distance between Station A and station B = Speed × time

= 80 × 3t

= 240t km

Similarly distance between station B and station C = 60 × t

= 60t

Now average speed between station A and station C = \frac{240t+60t}{(3t+t)}

= \frac{300t}{4t}

= 75 km per hour

4 0
3 years ago
Max found a pair of jeans on sale for 40 percent off. He used a coupon for an additional 20 percent off. If the original price o
Novay_Z [31]

Answer:

$27.2

Step-by-step explanation:

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What error might Anna have​ made? (Pls i have 10 min left i need this asap).
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Answer: A

Step-by-step explanation:

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3 years ago
Tell me if im wrong .. <br><br><br> 988 divided by 5 = 197..
Ainat [17]

Answer:

197.6

Step-by-step explanation:

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2 years ago
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