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Rus_ich [418]
2 years ago
9

Find dy/dx in the following 1) y=x^[10] +10^[x] +e^[x] 2) y=㏒ x +e^[x]+√x - 1/x

Mathematics
1 answer:
kakasveta [241]2 years ago
6 0

1. in picture 1

2. in picture 2

Hope this helps :T

Also I am not so shure about 2, but I am 98% shure 1 is right.

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What is 7.125 simplified as a fraction?
Luba_88 [7]

Answer: 7 \frac{1}{8} or \frac{57}{8}

Step-by-step explanation:

0.125 = 1/8

3 0
2 years ago
Use appropriate algebra and theorem 7. 2. 1 to find the given inverse laplace transform. (write your answer as a function of t.
ollegr [7]

The given function s/(s^2 +3s -4) is proved with the help of inverse Laplace theorem.

According to the statement

we have to find the inverse of the Laplace theorem with the help pf the given theorem in the statement.

So, For this purpose, we know that the

Laplace transformation is a transformation of a function f(x) into the function g(t) that is useful especially in reducing the solution of an ordinary linear differential equation with constant coefficients to the solution of a polynomial equation.

Now, We assume you want to find the inverse transform of s/(s^2 +3s -4).

This can be written in partial fraction form as

\frac{(4/5)}{(s+4)} + \frac{(1/5)}{(s-1)}

which can be found in a table of transforms to be the transform of

\frac{4}{5} e^{-4t} + \frac{1}{5} e^t

There are a number of ways to determine the partial fractions. They all start with factoring the denominator.

s^2 +3x -4 = (s+4)(s-1)

After that, you can postulate the final form and determine the values of the coefficients that make it so.

For example:

\frac{A}{(s+4)}  + \frac{B}{s-1}  = (A+B)s + \frac{(4B-A)}{(s^2 +3x -4)}

This gives rise to two equations:

(A+B) = 1

(4B-A) = 0.

So, The given function s/(s^2 +3s -4) is proved with the help of inverse Laplace theorem.

Disclaimer: This question was incomplete. Please find the full content below.

Question:

Use appropriate algebra and theorem 7.2.1 to find the given inverse laplace transform. (write your answer as a function of t.) ℒ−1 s s2 + 3s − 4.

Learn more about Laplace here

brainly.com/question/11630973

#SPJ4

3 0
2 years ago
What is the area, in square millimeters, of a right triangle with a hypotenuse of 68 millimeters and a leg of 60 millimeters?
Paladinen [302]
First, we have to solve the sides of the right triangle by using the Pythagorean theorem: a² + b² = c² where c is the length of the hypotenuse. Then, we can use the legs as length and height of the triangle and find the area by 1/2(base x height).

x² + 60² = 68²
x² + 3600 = 4624
x² = 1024
x = √1024
x = 32 = length of the other side

A = (1/2)(32) (60) = 960 mm²
6 0
3 years ago
The mean of a population being sampled is 64, and the standard deviation is 6. If the sample size is 50, the standard error of t
alexira [117]
<span><span><span>.........
.........
</span></span></span>the answer is .85
6 0
3 years ago
Someone please help!! i will<br> make you a brainliest...i don’t want to fail:(((
Serggg [28]

Answer:

the fisrt one is y=1/2x

the second one is y=x+11

the third one is y= x^3

fourth on is y= ^3 checkmark x

Step-by-step explanation: your welcome

8 0
2 years ago
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