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vredina [299]
3 years ago
11

A diameter of a circle is 16 units. What is the radius of the circle?

Mathematics
1 answer:
alekssr [168]3 years ago
6 0
R= diameter/2
answer: 8 units
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2. R(1, 1), 5(1,7), Т(5,7), U(5, 1); k =<br> 45<br> у<br> о<br> Help
Gekata [30.6K]
(5,7) because when you divide that’s the answer you get
8 0
3 years ago
Rosie washes clothes for two families the first family pays her $500 more per month than the second. Her total earning per month
disa [49]

Answer:

  • Family 1:  $1.850
  • Family 2: $1.350

Step-by-step explanation:

We know that the total monthly payment is 3200, so if we call Pa (family A`s payment) and Pb (Family B's payment) the payments:

  • Pa+Pb=3200
  • also, Pa = Pb+500

So if we replace Pa in the first ecuation:

  • Pb+500+Pb=3200
  • 2Pb= 3200-500
  • Pb=2700/2= $1.350

then Pa+Pb=3200 => Pa= 3200-1350= $1.850

Good Luck!

8 0
3 years ago
What is the simplest form of this expression?<br> -(х – 2)(3х2 + 4х-5)
skad [1K]

Answer:

C

Step-by-step explanation:

3x^2 * -x =-3x^3

3x^2 * 2. =6x^2

4x* -x =-4x^2

4x * 2 = 8x

-5 * -x = 5x

-5 * 2 = -10

6x^2 + -4x^2 = 2x^2

8x+5x = 13 x

Ans: -3x^3 + 2x^2 + 13x -10

7 0
3 years ago
Read 2 more answers
Simplify 0, -6 please :(
snow_tiger [21]

Answer:

You cant simplify it??????

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is the length side of a triangle that has vertices at (-5, -1), (-5, 5), and (3, -1)?
Rasek [7]

The side lengths of triangle are 6 units, 8 units and 10 units.

<u>SOLUTION: </u>

Given that, we have to find what is the length side of a triangle that has vertices at (-5, -1), (-5, 5), and (3, -1)  

We know that, distance between two points P\left(x_{1}, y_{1}\right) \text { and } Q\left(x_{2}, y_{2}\right) is given by  

P Q=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}

Now,  

\begin{array}{l}{\text { Distance between }(-5,-1) \text { and }(-5,5)=\sqrt{(-5-(-5))^{2}+(5-(-1))^{2}}} \\\\ {\qquad \begin{array}{l}{=\sqrt{(-5-(-5))^{2}+(5-(-1))^{2}}} \\\\ {=\sqrt{(0)^{2}+(5+1)^{2}}=\sqrt{(6)^{2}}=6} \\\\ {=\sqrt{(-5)^{2}+(5+1)^{2}+(5-(-1))^{2}}} \\\\ {=\sqrt{(-8)^{2}+(5+1)^{2}}=\sqrt{64+36}=\sqrt{100}=10} \\\\ {=\sqrt{(3-1)^{2}+(-1-(-1))^{2}}} \\\\ {=\sqrt{(5+3)^{2}+(0)^{2}}=\sqrt{(8)^{2}}=8}\end{array}}\end{array}

8 0
3 years ago
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