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Rashid [163]
3 years ago
10

Damon wants to grow grass in a backyard that is in the shape of a rectangle. The dimensions of the yard are shown in the

Mathematics
1 answer:
NeTakaya3 years ago
5 0

Answer:

279 ft^2

Step-by-step explanation:

The area of a rectangle of length L and width W is A = LW.

Here, that area is (19.25 ft)(14.5 ft) = 279.125 ft^2, or approx. 279 ft^2

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Which pair of numbers is the greatest common factor 15?​
gavmur [86]

Answer:

The answer is 3 and 5

Step-by-step explanation:

3 and 5 is 15 (correct)

10 and 25 is 250 (not correct)

30 and 60 is 1800 (not correct)

60 and 75 is 450 (not correct)

5 0
3 years ago
A basketball player is fouled while attempting to make a basket and receives two free throws. The opposing coach believes there
Elan Coil [88]
B not quiet sure but if anything try again : )
6 0
3 years ago
ANSWER PLZ QUICK AND FAST WHAT THE ANSWER
ki77a [65]

48 + 42a < 132

42a < 84

A < 2

7 0
3 years ago
How do you do the second part of the problem?
Sveta_85 [38]

Answer:

8

Step-by-step explanation:

According to the Alternating Series Estimation Theorem:

│aₙ₊₁│≤ ε

1 / (4 (n + 1)⁴) ≤ 0.00005

4 (n + 1)⁴ ≥ 20000

(n + 1)⁴ ≥ 5000

n + 1 ≥ 8.41

n ≥ 7.41

n must be an integer, so n ≥ 8.

7 0
4 years ago
How long will it take Greg to earn $500.00 round to the nearest hour
Mrrafil [7]

Answer:

56 hours

Step-by-step explanation:

we know that  

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form y/x=k or y=kx

Let

x -----> the number of hours

y ----> the amount earned in dollars

This problem represent a proportional relationship between the variable x and the variable y

Find the value of the constant of proportionality k

k=y/x

For (3,27) ----> k=27/3=9\ \$/h

For (9,81) ----> k=81/9=9\ \$/h

For (21,189) ----> k=189/21=9\ \$/h

The constant of proportionality k is 9

The linear equation is

y=9x

For y=$500

substitute in the equation and solve for x

500=9x

Divide by 9 both sides

x=56\ hours

5 0
3 years ago
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