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KengaRu [80]
4 years ago
10

How do you do the second part of the problem?

Mathematics
1 answer:
Sveta_85 [38]4 years ago
7 0

Answer:

8

Step-by-step explanation:

According to the Alternating Series Estimation Theorem:

│aₙ₊₁│≤ ε

1 / (4 (n + 1)⁴) ≤ 0.00005

4 (n + 1)⁴ ≥ 20000

(n + 1)⁴ ≥ 5000

n + 1 ≥ 8.41

n ≥ 7.41

n must be an integer, so n ≥ 8.

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Which expression represents each mathematical phrase?
olganol [36]

Answer:

Step-by-step explanation:

add 12 and a number: 12 + c

subtract a number from 12: 12 - c

divide a number by 12: c : 12 or c/12

multiply 12 by a number: 12 · c = 12c

5 0
3 years ago
PLEASEEEE HELP FOR BRAINLIST!!!!!!!!!
AysviL [449]

Same thing as before!

First, we can get rid of d(x) simply by looking at it because we can tell it's linear (it's a straight line). If we look at the table, we can see a(x) is also linear because it has a steady rate of growth. b(x) and c(x) both represent exponential growth. The curved shape of b(x) shows us this is exponential growth, and the exponent in c(x) tells us it's also exponential.

8 0
2 years ago
Please Help!
Flura [38]
Let x be the length of the train.

On the basis of the observer;
Speed of the train = x/6

On the basis of the bridge;
Total distance covered by any point of the train= 350+x
Speed = (350+x)/20

Equating the two expressions of speed;
x/6 = (350+x)/20
20(x) = 6(350+x)
20x = 2100+6x
(20-6)x = 2100
14x = 2100
x= 2100/14 = 150 m
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Therefore,
Length of train = 150 m
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8 0
3 years ago
What is the solution to the system of equations?<br><br> {y=5x−10y=−3x+14
Dahasolnce [82]

Answer:

x = 3 and y = 5

Step-by-step explanation:

Given equations are :

y=5x−10 ..(1)

y=−3x+14 ...(2)

Subtract equation (2) from (1).

y-y = 5x−10-(−3x+14)

0 = 5x-10+3x-14

0= 8x-24

8x = 24

x = 3

Put the value of x in equation (1).

y=5(3)−10

= 15-10

y = 5

So, the values of x and y are 3 and 5 respectively.

5 0
3 years ago
Add or subtract. Write the result in the form a+bi
STALIN [3.7K]

Number 1: (-1+2i)+(6-9i)

Group\:the\:real\:part\:and\:the\:imaginary\:part\:of\:the\:complex\:number\\\left(a+bi\right)\pm \left(c+di\right)=\left(a\:\pm \:c\right)+\left(b\:\pm \:d\right)i\\=\left(-1+6\right)+\left(2-9\right)i\\=5-7i

Number 2: (3-3i)-(4+7i)

Group\:the\:real\:part\:and\:the\:imaginary\:part\:of\:the\:complex\:number\\\left(a+bi\right)\pm \left(c+di\right)=\left(a\:\pm \:c\right)+\left(b\:\pm \:d\right)i\\=\left(3-4\right)+\left(-3-7\right)i\\Refine\\=-1-10i

Number 3: (-5+2i)+(-2+8i)

Group\:the\:real\:part\:and\:the\:imaginary\:part\:of\:the\:complex\:number\\\left(a+bi\right)\pm \left(c+di\right)=\left(a\:\pm \:c\right)+\left(b\:\pm \:d\right)i\\=\left(-5-2\right)+\left(2+8\right)i\\Refine\\=-7+10i

8 0
3 years ago
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