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trasher [3.6K]
3 years ago
10

Diameter = 28 cm. H = 25 cm.

Mathematics
1 answer:
nadezda [96]3 years ago
4 0
What’s the question?
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Mr green Drove 100 mies in 2 hours he continues to drive the same speed how long will mr green take to drive 400 more miles
tresset_1 [31]

Answer:

It would take him 8 hours

Since every 50 miles takes 1 hour

6 0
3 years ago
Read 2 more answers
Perform the indicated operation. 10 3/7 + 19 5/9
DanielleElmas [232]
Given expression is

10 \frac{3}{7} + 19 \frac{5}{9}

Now convert mixed fraction as improper fraction as

10 \frac{3}{7} + 19 \frac{5}{9} =  \frac{10*7 + 3}{7} +  \frac{19*9+5}{9}
                                                         =  \frac{73}{7}  +  \frac{176}{9}
                                                          =  \frac{73*9 + 176 * 7}{63}
                                                         =  \frac{657 + 1232}{63} =  \frac{1889}{63}
Now we can convert \frac{1889}{63 } = 29 \frac{62}{63}

So the answer is 29 \frac{62}63}
4 0
4 years ago
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What is the equation of the line that is parallel to y=6x−1 and passes through the point (−3,4)?
BabaBlast [244]

Answer: y = 6x + 22

Step-by-step explanation:

Parallel lines have same slope. So, a line parallel to y = 6x − 1 is y = 6x + c.

Now to find c, put (-3,4) to this equation since the line passes through the point.

4 = 6 × -3 + c

4 = -18 + c

4 + 18 = c

c = 22

So, equation is y = 6x + 22

3 0
3 years ago
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When using substitution to solve this system of equations
dlinn [17]
Hello, find the work out in the attached image
X = 4.5
Y = -1

3 0
3 years ago
Find the A.P whose second term is 12 and 7th term exceeds the 4th by 15
Art [367]

The 2nd term exists 12 and 7th term exceeds the 4th by 15 exists AP : 7,12,17,....

<h3>How to estimate the arithmetic progression?</h3>

Given : The second term exists 12th and the 7th term exceeds the 4th term by 15

The formula of the nth term :

$a_{n}=a+(n-1) d

Where d exists a common difference

n be the number of terms

a be the first term

Substitute the value of n = 2

$a_{2}=a+(2-1) d=a+d

Let, the second term exists 12

So, a + d = 12 ..........(1)

Substitute the value of n = 7

$a_{7}=a+(7-1) d=a+6 d

Substitute n = 4

$a_{4}=a+(4-1) d=a+3 d

We are given that the 7th term exceeds the 4th term by 15

So, a+6d-a-3d = 15

3d = 15

d = 5

Substitute the value of d in (1)

So, a+5 = 12

a = 12-5

a = 7

AP : a,a+d,a+2d,.... = 5, 7+5, 7+2(5),....=7,12,17,....

Therefore, AP : 7,12,17,....

To learn more about arithmetic progression refer to:

brainly.com/question/24191546

#SPJ9

4 0
2 years ago
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