Answer:
y<6
Step-by-step explanation:
You will solve it like a one-step equation but just leave the less then symbol. so anything less then 6 is your answer
The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.
Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>
We calculate the cross product as a determinant of (i,j,k) and the normal products
i j k
5 -1 -6
1 1 1
=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>
Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0
Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
Answer:
4096
Step-by-step explanation:
<em><u>Simplify:</u></em>
=((−4)3)2
=((−4)3)*((−4)3)
=((−4)*(−4)*(−4))*((−4)*(−4)*(−4))
=(−4)*(−4)*(−4)*(−4)*(−4)*(−4)
=(−4)6
<em><u>Step by Step:</u></em>
<u><em>((−4)3)2
</em></u>
<u><em>=(−64)2
</em></u>
<u><em>=4096</em></u>
<u><em /></u>
Answer: 4096
<em><u>Hope this helps.</u></em>
Answer: The correct answer is Tyrell, Yen, Hana....its C
Step-by-step explanation: Hope this helped :}
