The given equation is: 
To find the line perpendicular to it, we interchange coefficients and switch the signs of one coefficient.
The equation to a line perpendicular to it is:
$ 2y-x=c$
where, $c$ is some constant we have determine using the condition given.
It passes through $(2,-1)$
Put the point in our equation:
$2(-1)-(2)=c$
$c=-2-2$
$c=-4$
The final equation is:
$\boxed{ 2y-x=-4}$
Answer:
2) -5/7
Step-by-step explanation:
= 
cross-multiply to get:
10 = -14n
-10/14 = n
n = -5/7 (simplified)
Answer:
The point that the graph does not pass through is (3,1)
Step-by-step explanation:
we have
(0, 5), (2, 2), (3, 1), and (4, -1)
Draw the points, and join them to plot the linear equation and determine which point does not belong to the line.
using a graphing tool
see the attached figure
therefore
The point that the graph does not pass through is (3,1)
There is some disagreement whether parallelograms, which have two pairs of parallel sides, should be regarded as trapezoids. Some define a trapezoid as a quadrilateral having only one pair of parallel sides (the exclusive definition), thereby excluding parallelograms.
In other words, sometimes.