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Kisachek [45]
3 years ago
12

Save

Mathematics
2 answers:
Lubov Fominskaja [6]3 years ago
4 0
I’m so sorry I can’t figure it out 0512
Dvinal [7]3 years ago
3 0
Should of payed attention
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A researcher wishes to estimate within $5 the average repair cost of for a refrigerator. If she wishes to be 90% confident, how
Luda [366]

Answer:

The sample size 'n' = 26

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given a researcher wishes to estimate within $5 the average repair cost of for a refrigerator

Given estimate "E" = $5

<em>The  estimate within  the average is determined by</em>

<em>                 </em>E = \frac{Z_{0.10}S.D }{\sqrt{n} }<em></em>

<em>  Level of significance    ∝ = 90 % or 10% </em>

<em>                                             = 0.90 or o.10</em>

<em>Z₀.₁₀ = 1.645</em>

                                 E = \frac{Z_{0.10}S.D }{\sqrt{n} }

                             5 = \frac{1.645 X15.50 }{\sqrt{n} }

                        √n =  \frac{25.49}{5} = 5.099

Squaring on both sides , we get

                        n = 26

<u><em>Conclusion</em></u>:-

<em>The sample size 'n' = 26</em>

3 0
3 years ago
Explain how to write thirteen divided by thirty-three as a divison expression AND as a fraction!
sdas [7]
13÷33 is a division expression

13/33 is a fraction
5 0
4 years ago
Read 2 more answers
How do you solve 10=-2a
kykrilka [37]

Answer:

a=-5

Step-by-step explanation:

divide both sides by -2: -5=a

a=-5

8 0
3 years ago
Read 2 more answers
What is the width of todors area model? <br> 10x exponent2 -5x 15
mafiozo [28]

Answer:

The width of the area model is equal to

(2x^2-x+3)\ units

Step-by-step explanation:

<u><em>The complete question is</em></u>

Todor was trying to factor 10x^2-5x+15 he found the greatest common factor of these terms was 5 what is the width

we know that

The area of a rectangular model is given by the formula

A=LW ----> equation A

where

L is the length

W is the width

we have

A=10x^2-5x+15

Factor the expression

A=5(2x^2-x+3)

substitute the value of the Area in the equation A

5(2x^2-x+3)=LW

In this problem

The greatest common factor of these terms is the length (L=5 units)

so

we can say that the width is equal to (2x^2-x+3)

therefore

The width of the area model is equal to

(2x^2-x+3)\ units

5 0
3 years ago
Simplify 18 - 2[X + (x - 5)].<br> 8- 4x<br> 28 - 4x<br> 28 - 2x
malfutka [58]

Answer:

28 - 4x

Step-by-step explanation:

18 -2 [x + (x - 5)]  \\  = 18 - 2 [x + x - 5]  \\  = 18 - 2 [2x - 5] \\  = 18 -4x  + 10 \\  = 28 - 4x \\

5 0
4 years ago
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