How do you find the slope of (2, -6) & (-3, -4)

2 answers:

6 0

U use the slope formula
slope = (y2 - y1) / (x2 - x1)

and u label each set of points :
set 1 : (2,-6)...x1 = 2 and y1 = -6
set 2 : (-3,-4)...x2 = -3 and y2 = -4

now u sub...pay attention to ur signs
slope = (-4 - (-6) / (-3 - 2) = (-4 + 6) / -5 = 2/-5 = -2/5

marta [7]4 years ago

4 0

(-4)-(-6)/(-3)-2=

2/-5

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Neporo4naja [7]

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6 0

4 years ago

While constructing an equilateral triangle or a regular hexagon inscribed in a circle, you may have noticed that several smaller

Sauron [17]

Answer:

Using the transitive property of geometry, we proved that △PQR is an equilateral triangle.

Step-by-step explanation:

The diagram of the given scenario is in the attachment.

Here, PQ is the radius of circle Q

Also, PQ is the radius of circle P

Hence, circle-P and circle-Q have same radii.

Now, PQ=RQ as both are radii of circle Q

And PQ=PR, as both are radii of circle P

Hence as per transitive property, which states that, if any two angles, lines, or shapes are congruent to a third angle, line, or shape respectively, then the first two angles, lines, or shapes are also congruent to the third angle, line, or shape

PR=QR

Now, PQ = QR = PR

Hence, ∆PQR is equilateral.

For more explanation, refer the following link:

brainly.com/question/27884420

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