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tresset_1 [31]
2 years ago
7

What percent of $1.00 are a nickel and a dime?

Mathematics
1 answer:
Sliva [168]2 years ago
8 0

Answer:

Nickel = 5%

Dime = 10%

Nickel + Dime = 15%

Step-by-step explanation:

You can do this easily by dividing the value of each coin and dividing it by the value of a dollar and multiply it by 100%. But before you do that, you need to first make them the same unit.

Nickel = 5 cents

Dime = 10 cents

Dollar = 100 cents

Nickel:

\dfrac{5cents}{100cents} = 0.05

0.05 x 100% = 5%

Dime:

\dfrac{10cents}{100cents} = 0.10

0.10 x 100% = 10%

But if you are looking for the percentage of both a nickel and a dime together, just add them up and you'll get 15%.


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<h3><u>Wording Bias</u></h3>

The question asked in the survey contains certain characteristics that induce the respondent to think about the question asked in a negative way.

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2 years ago
In order to solve the following system of equations by addition, which of the
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Answer:

Multiply the top equation by -3 and the bottom equation by 2

Step-by-step explanation:

Given <u>system of equations</u>:

\begin{cases}4x-2y=7\\3x-3y=15 \end{cases}

To solve the given system of equations by addition, make one of the variables in both equations <u>sum to zero</u>.  To do this, the chosen variable must have the <u>same coefficient</u>, but it should be <u>negative</u> in one equation and <u>positive</u> in the other, so that when the two equations are added together, the variable is <u>eliminated</u>.

<u>To eliminate the </u><u>variable y</u>:

Multiply the top equation by -3 to make the coefficient of the y variable 6:

\implies -3(4x-2y=7) \implies -12x+6y=-21

Multiply the bottom equation by 2 to make the coefficient of the y variable -6:

\implies 2(3x-3y=15) \implies 6x-6y=30

Add the two equations together to <u>eliminate y</u>:

\begin{array}{l r r}& -12x+6y= &-21\\+ & 6x-6y= & 30\\\cline{1-3}& -6x\phantom{))))))} = & 9\end{array}

<u>Solve</u> for x:

\implies -6x=9

\implies x=-\dfrac{9}{6}=-\dfrac{3}{2}

<u>Substitute</u> the found value of x into one of the equations and <u>solve for y</u>:

\implies 3\left(-\dfrac{3}{2}\right)-3y=15

\implies -\dfrac{9}{2}-3y=15

\implies -3y=\dfrac{39}{2}

\implies y=-\dfrac{39}{2 \cdot 3}

\implies y=-\dfrac{13}{2}

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1 year ago
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Answer:

cdab

Step-by-step explanation:

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A body and tackle with a velocity ratio of 5 is used to raise a mass of 50kg through a vertical distance of 20n at a steady rate
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a. Distance moved by effort = 1 meter

b. Work done by effort = 80 Joules

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c. First, let's find the work output

Work output = m g h

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Losses in energy = 98 - 80

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