4 years ago

398.2235 to the nearest ten is what???

Mathematics

1 answer:

vazorg [7]4 years ago

5 0

The answer would be 400

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3 years ago

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Which 2 values of x are roots of the polynomial below?

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Given:

The given polynomial is:

$f(x)=$ $3x^{2}-3x+1$

To find the roots of the given polynomial.

To find the roots we have to take $f(x) = 0$

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$3x^{2} -3x+1 = 0$

Formula

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$x = \frac{-b+\sqrt{b^{2}-4ac } }{2a}$ and $\frac{-b-\sqrt{b^{2} -4ac} }{2a}$

Now,

Putting, $a=3, b=-3, c=1$ we get,

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Hence,

The values of the roots of the given polynomial are $x=\frac{3+\sqrt{-3} }{6}$ and $x=\frac{3-\sqrt{-3} }{6}$

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