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Mrrafil [7]
3 years ago
10

Anything to the power of 0 is always 1 right??

Mathematics
2 answers:
lana66690 [7]3 years ago
6 0
Yes, that is correct. 
Shtirlitz [24]3 years ago
4 0
Yes anything to the power of 0 is one in the contrary anything to the power of 1 its it self 

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I need help with the work
galben [10]
Okay. Mainly for these questions, we have to write out equations.

1. For the vacation days given in the U.S., that equation would be 25-n, because the U.S. gets fewer days than the Japanese worker does.
Equation: 25-n

2. The equation for this one would be 26s, because there are 26 grams of protein for each cup of cottage cheese. To find out the total amount of protein for all of the cups together, that equation works work out.
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3 0
3 years ago
Five thousand three hundred nine divided by forty three
Marizza181 [45]
123.4651163 or rounded to 123.47
4 0
4 years ago
Simplify the given expression. (16x^2 + 15xy – 19y^2) – (3x^2 – 3xy)
ruslelena [56]

Answer:

-19 y^2 + 18 x y + 13 x^2

Step-by-step explanation:

Simplify the following:

16 x^2 + 15 x y - 19 y^2 - (3 x^2 - 3 x y)

Factor 3 x out of 3 x^2 - 3 x y:

16 x^2 + 15 x y - 19 y^2 - 3 x (x - y)

-3 x (x - y) = 3 x y - 3 x^2:

16 x^2 + 15 x y - 19 y^2 + 3 x y - 3 x^2

Grouping like terms, 16 x^2 + 15 x y - 19 y^2 - 3 x^2 + 3 x y = -19 y^2 + (15 x y + 3 x y) + (16 x^2 - 3 x^2):

-19 y^2 + (15 x y + 3 x y) + (16 x^2 - 3 x^2)

x y 15 + x y 3 = 18 x y:

-19 y^2 + 18 x y + (16 x^2 - 3 x^2)

16 x^2 - 3 x^2 = 13 x^2:

Answer:  -19 y^2 + 18 x y + 13 x^2

4 0
3 years ago
Read 2 more answers
Help me I really need this rn
Andrews [41]

Answer:

the answer is 9 please I hope i get it right

6 0
3 years ago
Can 1 be expressed as a fraction
elixir [45]

  • <em><u>Any integer can be written as a fraction! Just put that integer as the numerator of a fraction with a denominator of 1.</u></em>

<h2><em><u>hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u>!</u></em></h2><h2><em><u>#</u></em><em><u>c</u></em><em><u>a</u></em><em><u>r</u></em><em><u>r</u></em><em><u>y</u></em><em><u> </u></em><em><u>on </u></em><em><u>learning</u></em></h2>

6 0
2 years ago
Read 2 more answers
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