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8_murik_8 [283]
3 years ago
15

What is Perfect squares?

Mathematics
2 answers:
lesya692 [45]3 years ago
6 0
The product of a rational number multiplied by itself 
sashaice [31]3 years ago
4 0
A perfect square is a number that can be expressed as the product of two equal integers.
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Which are the solutions of the quadratic equation? x^2 = –5x – 3
ollegr [7]
<span>x=<span><span><span>−5</span>2</span>+<span><span><span><span>12</span><span>√13</span></span><span> or </span></span>x</span></span></span>=<span><span><span>−5</span>2</span>+<span><span><span>−1</span>2</span><span>√<span>13</span></span></span></span>
3 0
3 years ago
Can you guys help me wit number 7 please nn thanks
Vaselesa [24]

Answer:

10 to the power 3

Step-by-step explanation:

10 to the power 6 divided by 10 to the power 3 is 10 to the power 3.

3 0
2 years ago
Dylan purchased a new car in 1993 for $26,300. The value of the car has been depreciating exponentially at a constant rate. If t
emmainna [20.7K]

The predicted value of the car in the year 2006 to the nearest dollar would be  $651.

<h3>What is the predicted value of the car?</h3>

The first step is to determine the rate of depreciation

g = (FV/PV)^(1/n) - 1

Where:

FV = value of the car in 2001

PV = value of the car in 1993

n = number ofyears = 8

(2700/26,300)^(1/8) - 1  = -24.76%

Now determine the value of the car in 2006

2700x ( 1 - 0.2476)^5 = $651

To learn more about depreciation, please check: brainly.com/question/25552427

8 0
2 years ago
Find the following quotients, and write the quotient in standard form. (a)- x^2-9 ÷ x-3 (b)- x^3-27 ÷ x-3 (c) x^4- 81 ÷ x-3
IgorLugansk [536]

Answer:

(a) x+3

(b) x^2+3x+9

(c) (x+3)(x^2+9)

Step-by-step explanation:

We have given that

(a) \frac{x^2-9}{x-3}

From the algebraic identity we know that

a^2-b^2=(a+b)(a-b)

So \frac{x^2-9}{x-3}=\frac{(x+3)(x-3)}{x-3}=x+3

(b) \frac{x^3-27}{x-3}

We know the algebraic identity

a^3-b^3=(a-b)(a^2+ab+b^2)

So \frac{x^3-27}{x-3}=\frac{x^3-3^3}{x-3}=\frac{(x-3)(x^2+3x+9)}{x-3}=x^2+3x+9

(c) We have given \frac{x^4-81}{x-3}

We know the algebraic identity

a^2-b^2=(a+b)(a-b)

\frac{x^4-81}{x-3}=\frac{(x^2)^2-(3^2)^2}{x-3}=\frac{(x^2-9)(x^2+9)}{x-3}=\frac{(x+3)(x-3)(x^2+9)}{x-3}=(x+3)(x^2+9)

3 0
3 years ago
the fun house allows 35 people in at a time but there is cure tally 110 ppl in line how many groups get to go in before every bo
BlackZzzverrR [31]

35×3=105 with 5 left over

So it would be 4 group

3 groups of 35 and 1 group of 5

So it would be 4 groups

Step-by-step explanation:

4 0
3 years ago
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