Answer:
Quadrilateral FSHB∼quadrilateral KTWJ.
Step-by-step explanation:
Given two quadrilaterals we have to prove these two similar.
The two quadrilaterals are similar if the corresponding sides of these are proportional then only the quadrilateral are proportional i.e
∴ 
If the above condition satisfied then the quadrilateral are similar.
Let us find these ratios
All ratios are equal.
Hence, the corresponding sides and angles of these two quadrilaterals are proportional implies that these two are similar i.e quadrilateral FSHB∼quadrilateral KTWJ.
You can determine if the answer is positive or negative because the even numbers are positive and the odd numbers are negative
Answer:
11.8294Step-by-step explanation:
Recall that A = 1/2bh.
We are given that h = 4+2b
So, putting it all together:
168 = 1/2 b(4+2b)
168 = 1/2(4b + 2b^2)
168 = 2b + b^2
b^2 + 2b - 168 = 0.
Something that multiplies to -168 and adds to 2? There's a trick to this.
Notice 13^2 = 169. So, it's more than likely in the middle of the two numbers we're trying to find. So let's try 12 and 14. Yep. 12 x 14 = 168. So this factors into (b+14)(b-12) So b = -14 or b =12. Is it possible to have a negative length on a base? No. So 12 must be our answer.
Let's check this. If 12 is our base, then according to our problem, 2*12 + 4 would be our height... or 28. so what is 12 * 28 /2?
196. Check.
Hope this helped!
